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nika2105 [10]
3 years ago
5

Find the quotient

Mathematics
2 answers:
Sindrei [870]3 years ago
8 0

Answer:

1) 2.3

2) 4.088

3) .416

4) 12.52

5) 1012.5

Step-by-step explanation:

Harman [31]3 years ago
6 0

Answer:

1). 2

2). 4.088

3). 0

4). 12.52

5). 1012.5

Step-by-step explanation:

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Brut [27]
1. 3 + 6 + 9 = 18
18/3 = 6 --> The average is 6
2. 15 + 5 + 8 + 4 = 32
32/4 = 8 --> The average is 8
3. 6 + 10 + 5 = 21
21/3 = 7 --> The average is 7
4. 14 + 9 + 7 = 30
30/3 = 10 --> The average is 10
6 0
3 years ago
Apply the distributive property to the expression 7(2x - 8y - 6) to produce an equivalent expression.
MaRussiya [10]

Answer:

14x-56y-42

Step-by-step explanation:

Given data

We have the expression

7(2x - 8y - 6)

Open the bracket we have

14x-56y-42

Hence the equivalent expression is

14x-56y-42

4 0
3 years ago
Military radar and missile detection systems are designed to warn a coutry of an enemy attack. Assume that a particular detectio
Tom [10]

Answer:

0.96 = 96% probability that at least one of them detect an enemy attack.

Step-by-step explanation:

For each radar, there are only two possible outcomes. Either it detects the attack, or it does not. The missiles are operated independently, which means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Assume that a particular detection system has a 0.80 probability of detecting a missile attack.

This means that p = 0.8

If two military radars are installed in two different areas and they operate independently, the probability that at least one of them detect an enemy attack is

This is P(X \geq 1) when n = 2. So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.8)^{0}.(0.2)^{2} = 0.04

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.04 = 0.96

0.96 = 96% probability that at least one of them detect an enemy attack.

6 0
3 years ago
Which expression is equivalent to 3a^2b•4bc^2
Mice21 [21]

Answer

Step-by-step explanation:

C

8 0
2 years ago
Kurt attended music classes for 1/6 of a year. Then he attended swimming classes for 1/4 of a year. What fraction of a year, in
Marysya12 [62]

Answer:

i think its b cause it states it in the math problem and other things

Step-by-step explanation:

5 0
3 years ago
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