Answer:
Matter have two essential types of properties, those are physical properties and chemical properties.
Explanation:
Answer:
Vy = 80.5 [m/s]
Explanation:
In order to solve this problem we must use the Pythagorean theorem.
V = 90 [m/s]
The components are Vx and Vy:
Therefore:

where:
Vy = 2*Vx ; because one is twice of the other.
![90 = \sqrt{v_{x}^{2} +(2*v_{x})^{2} }\\ 90 =\sqrt{v_{x}^{2}+4*v_{x}^{2}} \\90 =\sqrt{5v_{x}^{2}} \\90=2.23*v_{x} \\v_{x}=40.25[m/s]](https://tex.z-dn.net/?f=90%20%3D%20%5Csqrt%7Bv_%7Bx%7D%5E%7B2%7D%20%20%2B%282%2Av_%7Bx%7D%29%5E%7B2%7D%20%7D%5C%5C%2090%20%3D%5Csqrt%7Bv_%7Bx%7D%5E%7B2%7D%2B4%2Av_%7Bx%7D%5E%7B2%7D%7D%20%5C%5C90%20%3D%5Csqrt%7B5v_%7Bx%7D%5E%7B2%7D%7D%20%5C%5C90%3D2.23%2Av_%7Bx%7D%20%5C%5Cv_%7Bx%7D%3D40.25%5Bm%2Fs%5D)
and the bigger vector is:
Vy = 40.25*2
Vy = 80.5 [m/s]
Answer:
120 m
Explanation:
Given:
wavelength 'λ' = 2.4m
pulse width 'τ'= 100T ('T' is the time of one oscillation)
The below inequality express the range of distances to an object that radar can detect
τc/2 < x < Tc/2 ---->eq(1)
Where, τc/2 is the shortest distance
First we'll calculate Frequency 'f' in order to determine time of one oscillation 'T'
f = c/λ (c= speed of light i.e 3 x
m/s)
f= 3 x
/ 2.4
f=1.25 x
hz.
As, T= 1/f
time of one oscillation T= 1/1.25 x
T= 8 x
s
It was given that pulse width 'τ'= 100T
τ= 100 x 8 x
=> 800 x
s
From eq(1), we can conclude that the shortest distance to an object that this radar can detect:
= τc/2 => (800 x
x 3 x
)/2
=120m