All categories

2 years ago

The average 8-18 year old spends how many hours per day average in front of a screen doing little physical activity

Physics

1 answer:

Ne4ueva [31]2 years ago

5 0

Nearly four hours every day, doing little to no physical activity.

You might be interested in

A battery has a potential resistance of 12 V and a current of 1280 mA. What is the resistance? PLS HELP ME ASAPPPPPPPPPP

Romashka-Z-Leto [24]

Resistance (R) = <u>9.375 ohm (Ω)</u>

Steps:

$R = \frac{V}{I}$

$= \frac{12 \: volt}{1280 \: milliampere}$

$= \frac{12 \: volt}{1.28 \: ampare}$

$= 9.375 \: ohm (Ω)$

6 0

2 years ago

Doug is doing work. Without knowing exactly what he is doing, which can be said about the work he is doing?

WARRIOR [948]

<h3>Answer;</h3>

<em>Energy is transferred.</em>

<h3>Explanation;</h3>

Work is the force applied over a given distance, in other words work is the product of force and distance. That is; Work = force × distance.
Work is measured in Joules.

Energy on the other hand, is the ability to do work.

According to the principle of work-energy a change in the kinetic energy is equivalent to the net work don e by the object. Therefore, when work is being done energy is being transferred from one point to another.

8 0

3 years ago

Read 2 more answers

The work-energy theorem states that a force acting on a particle as it moves over a ______ changes the ______ energy of the part

svetoff [14.1K]

Answer:

B. distance/potential

Explanation:

Quizlet

5 0

2 years ago

If an X-ray beam of wavelength 1.4 × 10-10 m makes an angle of 20° with a set of planes in a crystal causing first order constru

Flura [38]

Answer:

43.16°

Explanation:

λ = Wavelength = 1.4×10⁻¹⁰ m

θ₁ = 20°

n can be any integer

d = distance between the two slits

Since for the first bright fringe, n₁ = 1

n₂ = 2 for second order line

The relation between the distance of the slits and the angle through which it is passed is:

dsinθ=nλ

As d and λ are constant

$\frac{n_1\lambda}{sin \theta_1}=\frac{n_2\lambda}{sin \theta_2}\\\Rightarrow \frac{1}{sin20}=\frac{2}{sin\theta_2}\\\Rightarrow sin\theta_2=\frac{2}{\frac{1}{sin20}}\\\Rightarrow \theta_2=sin^{-1}{\frac{2}{\frac{1}{sin20}}}\\\Rightarrow \theta_2=43.16^{\circ}$