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3 years ago

5

The principal of uniformitarian states that

1 answer:

Akimi4 [234]3 years ago

4 0

It started that the present is the key to the past. The process that we see in operation today are the same ones that have operated in the geologic past.

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1. What are 3 main categories of waste and what is the largest contribution of municipal solid waste?

Tasya [4]

Organic materials continue to be the largest component of MSW. Paper and paperboard account for 27 percent and yard trimmings and food account for another 28 percent. Plastics comprise about 13 percent; metals make up 9 percent; and rubber, leather, and textiles account for 9 percent.

5 0

3 years ago

Find the reaction supports at Ta and TB as shown in the loaded beam.

koban [17]

ANSWER

$\begin{gathered} T_A=17.5N \\ T_B=12.5N \end{gathered}$

EXPLANATION

First, we have to make a sketch of the direction of the moments of the forces about 12m from the left in the diagram:

The sum of upward forces must be equal to the sum of downward forces. This implies that:

$\begin{gathered} T_A+T_B=20+10 \\ T_A+T_B=30N \end{gathered}$

Also, the sum of clockwise moments must be equal to the counter-clockwise moments:

$\begin{gathered} (20\cdot8)+(T_B\cdot4)=(T_A\cdot12) \\ 160+4T_B=12T_A \\ \Rightarrow12T_A-4T_B=160 \end{gathered}$

From the first equation, make TA the subject of the formula:

$T_A=30-T_B$

Substitute that into the second equation:

$\begin{gathered} 12(30-T_B)-4T_B=160 \\ 360-12T_B-4T_B=160 \\ -16T_B=160-360=-200 \\ T_B=\frac{-200}{-16} \\ T_B=12.5N \end{gathered}$

Substitute that into the equation for TA:

$\begin{gathered} T_A=30-12.5 \\ T_A=17.5N \end{gathered}$

Therefore, the reaction supports at TA and TB are:

$\begin{gathered} T_A=17.5N \\ T_B=12.5N \end{gathered}$

5 0

1 year ago

A race car starts from rest on a circular track of radius 478 m. The car’s speed increases at the constant rate of 0.747 m/s 2 .

Keith_Richards [23]

Answer:

18.896ms-1

Explanation:

The tangential acceleration of the car= 0.747ms-2

The centripetal acceleration is given by v^2/r

0.747= v^2/r

V= √0.747*478= 18.896ms-1

3 0

4 years ago

The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of t

mel-nik [20]

Answer:

It will take 0.0611 sec for nerve signal to travel 1.1 m

Explanation:

We have given the nerve cell connecting the spinal card to feet is 1.1 m long

So length d = 1.1 m

And speed of the nerve impulse v = 18 m/sec

We have to find the time for nerve signal to travel that distance

Speed of the nerve signal is given by $v=\frac{d}{t}$

So $t=\frac{d}{v}=\frac{1.1}{18}=0.0611sec$

So it will take 0.0611 sec for nerve signal to travel 1.1 m

5 0

3 years ago

A thermostat is used for which of the following? maintaining the temperature in a room turning a heating system on turning a hea

Molodets [167]

All of the above, it's a very useful device :P

4 0

3 years ago

Read 2 more answers