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patriot [66]
3 years ago
6

who plays adopt me on rob.lox!! plz answer people only if you play though tell me your best pet and your user name so we can pla

y!!
Physics
2 answers:
gladu [14]3 years ago
6 0

Answer:

adopt me sucks but my best pet was an albino monkey I think or a king monkey

Explanation:

densk [106]3 years ago
3 0

Answer: I don't  do   adopt me   but I do have a Ro.blox username its  Nvm i cant but my user name

Explanation:

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A bucket filled with water has a mass of 54 kg and is hanging from a rope that is wound around a 0.050 m radius stationary cylin
Lubov Fominskaja [6]

Answer:

The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

Explanation:

Given that,

Mass of bucket = 54 kg

Radius = 0.050 m

We need to calculate the magnitude of the torque the bucket produces around the center of the cylinder

Using formula of torque

\tau=F\times r

\tau=mg\times r

Where, m = mass

g = acceleration due to gravity

r = radius

Put the value into the formula

\tau=54\times9.8\times0.050

\tau=26.46\ N-m

Hence, The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

3 0
3 years ago
A pendulum has a period of 0.500. What is its length?
qwelly [4]
It's about 6 cm long
6 0
3 years ago
I NEED HELP ASAP
zzz [600]

Answer:

I believe the answer is C

Explanation:

because centripetal force is generally assosiated with rotation and how fast something spins

3 0
3 years ago
A 129-kg horizontal platform is a uniform disk of radius 1.51 m and can rotate about the vertical axis through its center. A 67.
blondinia [14]

Answer:

I = 274.75 kg-m²

Explanation:

given,

mass of horizontal platform = 129 Kg

radius of the disk = 1.51 m

mass of the person(m_p) = 67.5 Kg

standing at distance(r_p) = 1.09 m

mass of dog(m_d) = 25.3 Kg

sitting near the person(r_d) = 1.37 m from center

moment of inertia = ?

Moment of inertia of disc = \dfrac{1}{2}MR^2

Moment of inertia of the system

I = MOI\ of\ disk + m_p r_p^2 + m_d r_d^2

I = \dfrac{1}{2}MR^2 + m_p r_p^2 + m_d r_d^2

I = \dfrac{1}{2}\times 129 \times 1.51^2 + 67.5 \times 1.09^2 + 25.3\times 1.37^2

I = 274.75 kg-m²

3 0
3 years ago
Based on your calculations in Activity 3.7B, what are the rates of seafloor spreading for the North Atlantic basin ______cm/yr
Over [174]
It was be at least 67 cm/yr for the North Atlantic
3 0
3 years ago
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