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IRISSAK [1]
3 years ago
15

If you double the pressure on the surface of a can of water, the buoyant force on a stone placed in that water will

Physics
1 answer:
Bingel [31]3 years ago
4 0
The buoyant force won't change.
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An autotransformer is used to reduce the voltage of a 100-kilovolt amp, 480-volt secondary of an isolated type transformer, to s
tigry1 [53]

Answer:

42KVA

Explanation:

Given data

High Voltage (HV)= 480V

Low Voltage (LV)= 277V

Fo find

Size of transformer=?

Solution

To find the size of transformer here we use the co-ratio.The Co-ratio is given as:

Co-Ratio= (HV - LV)/HV

where

HV is High Voltage

LV is Low Voltage

Now put the values we get

Co- Ratio=(480-277)/480=.42

So the size of transformer is 42KVA

5 0
3 years ago
Quick! how did Daniel hale Williams contribute to science?
My name is Ann [436]
He preformed the first ever successful open heart surgery
3 0
3 years ago
Convert 9.75 millimeters to centimeter​
Butoxors [25]

Answer:

0.975cm

Explanation:

7 0
3 years ago
Read 2 more answers
Wнιcн deмonѕтraтeѕ condυcтιon
jekas [21]

C.) cool feet walking across a hot pavement.



The reason because the other ones deals with radiation. Only C.) is the right answer because the feet is touching the hot pavement which is conduction. 
3 0
3 years ago
A charged wire of negligible thickness has length 2L units and has a linear charge density λ. Consider the electric field E-vect
Stels [109]

Answer:

E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

Explanation:

Given that

Length= 2L

Linear charge density=λ

Distance= d

K=1/(4πε)

The electric field at point P

E=2K\int_{0}^{L}\dfrac{\lambda }{r^2}dx\ sin\theta

sin\theta =\dfrac{d}{\sqrt{d^2+x^2}}

r^2=d^2+x^2

So

E=2K\lambda d\int_{0}^{L}\dfrac{dx }{(x^2+d^2)^{\frac{3}{2}}}

Now by integrating above equation

E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

4 0
3 years ago
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