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4 years ago

What could you do to increase the electric potential energy between two positively charged particles by a factor of 16?

2 answers:

ivann1987 [24]4 years ago

6 0

$Electric~potential ~energy~U_{E}=K_{e}.\dfrac{Qq}{R}\\so~ U_{E} \propto \dfrac{1}{R}$
so to increase Ue by 16 times you gotta reduce R(distence) by 16 times

inysia [295]4 years ago

3 0

Answer:

Increase the charge of one particle by a factor of 16

Explanation:

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ankoles [38]

Answer:

Part a)

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Part b)

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Explanation:

Part a)

As we know that the magnetic force on the current carrying wire is given as

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so we have

$F = iLB sin\theta$

$F = (0.50)(0.30)(0.5 \times 10^{-4}) sin38$

so we have

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Part b)

Now magnetic field is changed to 0.55 T

so we will have

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3 years ago

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jasenka [17]

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4 years ago

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HACTEHA [7]

Answer:

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Explanation:

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I hope you find this information useful and interesting! Good luck!

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sergiy2304 [10]

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Explanation:

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3 years ago

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Dafna1 [17]

Answer:

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Explanation:

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