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Wittaler [7]
4 years ago
13

What could you do to increase the electric potential energy between two positively charged particles by a factor of 16?

Physics
2 answers:
ivann1987 [24]4 years ago
6 0
Electric~potential ~energy~U_{E}=K_{e}.\dfrac{Qq}{R}\\so~ U_{E} \propto \dfrac{1}{R}
so to increase Ue by 16 times you gotta reduce R(distence) by 16 times
inysia [295]4 years ago
3 0

Answer:

Increase the charge of one particle by a factor of 16

Explanation:

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A body has a mass of 2kg.it accelerats from 20m/s to 40m/s in 4 seconds.the resultant force is<br>​
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The resultant force is 8N  

Given that mass is 2kg , v= 40m/s, u =20m/s and we need to calculate resultant force
F=ma

m is given
so for a
v-u/t=a { first equation of motion }

40-20/4= 4
so a=4

F = ma =2*4 = 8N
The difference between the forces that are acting on an object as part of a system is known as the resultant force.
v = u + at is the first equation of motion. Here, v denotes the end speed, u the starting speed, an acceleration, and t the passage of time. The first equation of motion is provided by the velocity-time relation, which may be used to calculate acceleration.

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jeka94

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A car of mass 800 kg is travelling at 30 m/S. The car then brakes suddenly and stops with a braking distance of 75 m find the wo
gulaghasi [49]

Answer:

-360 kJ

Explanation:

Given:

m = 800 kg

v₀ = 30 m/s

v = 0 m/s

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We can solve this using either forces or energy.

To use forces, first find the acceleration.

v² = v₀² + 2aΔx

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a = -6 m/s²

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W = -360,000 J

W = -360 kJ

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