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marusya05 [52]
3 years ago
6

(NECESITO PROCEDIMIENTO) 9x + 8 = 7x + 6 X= -1 X= 1/3 X= 1

Mathematics
1 answer:
Aloiza [94]3 years ago
7 0

Answer:

x=-1

Step-by-step explanation:

9x+8=7x+6

Keep the variables in the left side & rest in the left side:

9x-7x=6-8

2x=-2

x=-2/2

x=-1

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Read 2 more answers
Linear Function Table
Andrej [43]

a. The difference between two outputs that are 1 unit apart.

You need to Use y2 - y1 / x2 - x1 to find the difference

I will choose x2 as 1 and x1 as 0

(29 - 21) / (1 - 0)

8/1 so The difference is 8 per 1 unit.

b. Use the same formula

I will choose -3 as x2 and -5 as x1

(5 - (-11)) / (-3 - (-5))

(5 + 11) / (-3 + 5)

16 / 2 so the difference is 16 per 2 units.

c. I will choose 2 as x2 and -1 as x1

(45 - 21) / (2 - (-1))

24/3 so the difference is 24 per 3 units.

d. The ratios of the differences to the input intervals reduced all equal each-other, which is 8 per 1 unit.

4 0
3 years ago
Solve the equation 2cosA = 3tanA
zavuch27 [327]
\bf sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)
\\\\\\
tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}\\\\
-----------------------------\\\\

2cos(A)=3tan(A)\implies 2cos(A)=3\cfrac{sin(A)}{cos(A)}
\\\\\\
2cos^2(A)=3sin(A)\implies 2[1-sin^2(A)]=3sin(A)
\\\\\\
2-2sin^2(A)=3sin(A)\implies 2sin^2(A)+3sin(A)-2

\bf \\\\\\
0=[2sin(A)-1][sin(A)+2]\implies 
\begin{cases}
0=2sin(A)-1\\
1=2sin(A)\\
\frac{1}{2}=sin(A)\\\\
sin^{-1}\left( \frac{1}{2} \right)=\measuredangle A\\\\
\frac{\pi }{6},\frac{5\pi }{6}\\
----------\\
0=sin(A)+2\\
-2=sin(A)
\end{cases}

now, as far as the second case....well, sine of anything is within the range of -1 or 1, so -1 < sin(A) < 1

now, we have -2 = sin(A), which simply is out of range for a valid sine, so there's no angle with such sine

so, only the first case are the valid angles for A
8 0
3 years ago
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