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ZanzabumX [31]
2 years ago
7

Joe can weed the garden twice as fast as his sister Janet. Together they can weed the garden in 2 hours. How long would it take

each of them working alone?
A:\:\left(\:\frac{1\:}{x}\:\right)\:\cdot 4+\:\left(\frac{1\:}{2x}\:\right)\cdot 2\:=\:1

B:\Large{ ( \frac {1}{x} ) + (\frac {1}{2x} ) = 1}

C:\Large{ ( \frac {1}{x} ) + (\frac {1}{2x} ) = 2}

D:\Large{ ( \frac {1}{x} ) \cdot 2 + (\frac {1}{2x} ) \cdot 2 = 1}
Mathematics
1 answer:
gavmur [86]2 years ago
3 0

Answer: use waymath mut type the other way around

Step-by-step explanation:

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IM ON THE SAME ONEEE let me know when you have it

Step-by-step explanation:

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Realtions??? IDK someone please explain
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What is the length of angle EF in the right triangle below?
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2 years ago
From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.
zzz [600]

Answer: (20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}

, where \overline{x} = sample mean.

z*= critical z-value

n= sample size.

\sigma = Population standard deviation.

By considering the given question , we have

\overline{x}= 21.69

\sigma=3.23

n= 58

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}

=21.69\pm (1.96)\dfrac{1.7}{7.61577}

=21.69\pm (1.96)(0.223221)

\approx21.69\pm0.83

=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

7 0
3 years ago
Simplify .√15 x √12​
skad [1K]

Answer:

6√5

Step-by-step explanation:

√15 x √12

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=3 x 2 x √5

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8 0
3 years ago
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