2 years ago

NEED HELP!!! please:)

Mathematics

1 answer:

Dahasolnce [82]2 years ago

8 0

No, Jonah is not correct. The answer is shown in the picture.

You might be interested in

I dont understand plz help<br><br> plz i am timed i have 8 mins left plz help me

KiRa [710]

Answer: the answer is a

7 0

2 years ago

Solve the Inequality Give 5 solutions of the inequality ( Show your solution).<br> 2x -3 < 5

marysya [2.9K]

Answer:

Inequality Form:

x<4

1<4

3<4

-1004<4

Interval Notation:

(−∞,4)

(-1004,4)

(3,4)

(1,4)

Step-by-step explanation:

5 0

3 years ago

What is the answer for 14a³ - 22a we have to Factorise it

sveta [45]

Answer: 2a (7a² - 11).

5 0

2 years ago

Read 2 more answers

Some help with the circle problem would be much aprecated.

Oksana_A [137]

Try this solution:
for the circle A: circumference=6π, area=9π
for the circle B: circumference=12π, area=36π

PS. formula for circumference is 'L=2πr', for area is 'S=πr²'.

8 0

2 years ago

Identify the zeros of the function f(x) = 4x2 − 8x − 1 using the Quadratic Formula. HELP ASAP!!

forsale [732]

$1+\dfrac{\sqrt{5}}{2},1-\dfrac{\sqrt{5}}{2}$

Step-by-step explanation:

The given equation is $4x^{2}-8x-1$

Let $a$ be the coefficient of $x^{2}$

Let $b$ be the coefficient of $x$

Let $c$ be the constant.

Then the roots α,β for the equation $ax^{2}+bx+c$ are $\dfrac{-b+\sqrt{b^{2}-4ac} }{2a},\dfrac{-b-\sqrt{b^{2}-4ac} }{2a}$

So,α= $\frac{-b+\sqrt{b^{2}-4ac} }{2a}=\frac{8+\sqrt{64+16} }{8}=\frac{8+4\sqrt{5}}{8}=1+\frac{\sqrt{5}}{2}$

β= $\frac{-b-\sqrt{b^{2}-4ac} }{2a}=\frac{8-\sqrt{64+16} }{8}=\frac{8-4\sqrt{5}}{8}=1-\frac{\sqrt{5}}{2}$ .

So the roots are $1+\frac{\sqrt{5}}{2},1+\frac{\sqrt{5}}{2}$

5 0

2 years ago