All categories

3 years ago

NEED HELP!!! please:)

Mathematics

1 answer:

Dahasolnce [82]3 years ago

8 0

No, Jonah is not correct. The answer is shown in the picture.

You might be interested in

Suppose the probability that a softball player gets a hit in any single at-bat is 0.300. Assuming that her chance of getting a h

Ksivusya [100]

Answer:

$P(X=4)=(1-0.3)^{4-1} 0.3 = 0.103$

The probability that she will not get a hit until her fourth time at bat in a game is 0.103

Step-by-step explanation:

Previous concepts

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

$P(X=x)=(1-p)^{x-1} p$

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

$X\sim Geo (1-p)$

Solution to the problem

For this case we want this probability

$P(X=4)$

And using the probability mass function we got:

$P(X=4)=(1-0.3)^{4-1} 0.3 = 0.103$

The probability that she will not get a hit until her fourth time at bat in a game is 0.103

4 0

3 years ago

Sara tried to evaluate 21 : 7 x 8 step-by-step

nlexa [21]

Answer: Sara multiplied by 3 when she should have multiplied by 8.

Step-by-step explanation:

21 : 7*8

7*8 = 56

21 : 56

The simplest form of this ratio is 3 : 8

6 0

3 years ago

Easy geometry question about rhombus/measures :))

OLEGan [10]

Answer:

∠1 = 51

∠2= 51

∠3= 39

∠4= 51

3 0

3 years ago

How do you write 3 times 3/5 as a mixed number

Korolek [52]

1 4/5
Hope it helps! :)

7 0

3 years ago

Read 2 more answers

1. y = x2 + 8x + 15<br> Find the zeros of the function by rewriting the function in intercept form

lubasha [3.4K]

The zeros of given function $y=x^{2}+8 x+15$ is – 5 and – 3

<u>Solution:</u>

$\text { Given, equation is } y=x^{2}+8 x+15$

We have to find the zeros of the function by rewriting the function in intercept form.

By using intercept form, we can put value of y as to obtain zeros of function

We know that, intercept form of above equation is $x^{2}+8 x+15=0$

$\text { Splitting } 8 x \text { as }(5+3) x \text { and } 15 \text { as } 5 \times 3$

$\begin{array}{l}{\rightarrow x^{2}+(5+3) x+5 \times 3=0} \\\\ {\rightarrow x^{2}+5 x+3 x+5 \times 3=0}\end{array}$

Taking “x” as common from first two terms and “3” as common from last two terms

x (x + 5) + 3(x + 5) = 0

(x + 5)(x + 3) = 0

Equating to 0 we get,

x + 5 = 0 or x + 3 = 0

x = - 5 or – 3

Hence, the zeroes of the given function are – 5 and – 3

5 0

3 years ago