Question

Consider the following function: f(x)=-3/4x+9

Answer 1

Answer:

$f^{-1}(x) = ( \frac{4y - 36}{-3} )$

Step-by-step explanation:

f(x)=-3/4x+9

let f(x) be y .......................to find inverse we have making x the subject.

y = -3/4x+9

y - 9 = -3/4 x

-3x = 4y - 36

x = (4y - 36)/-3

so, $f^{-1}(x) = ( \frac{4y - 36}{-3} )$

Answer 2

• Let y=f(x)

$\\ \tt\hookrightarrow y=\dfrac{-3}{4}x+9$

$\\ \tt\hookrightarrow y-9=\dfrac{-3x}{4}$

$\\ \tt\hookrightarrow -3x=4y-36$

$\\ \tt\hookrightarrow x=\dfrac{-4}{3}y+12$

Now

$\\ \tt\hookrightarrow f^{-1}x=\dfrac{-4}{3}x+12$