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2 years ago

Consider the following function: f(x)=-3/4x+9

Mathematics

2 answers:

miv72 [106K]2 years ago

8 0

Answer:

$f^{-1}(x) = ( \frac{4y - 36}{-3} )$

Step-by-step explanation:

f(x)=-3/4x+9

let f(x) be y .......................to find inverse we have making x the subject.

y = -3/4x+9

y - 9 = -3/4 x

-3x = 4y - 36

x = (4y - 36)/-3

so, $f^{-1}(x) = ( \frac{4y - 36}{-3} )$

rusak2 [61]2 years ago

8 0

Let y=f(x)

$\\ \tt\hookrightarrow y=\dfrac{-3}{4}x+9$

$\\ \tt\hookrightarrow y-9=\dfrac{-3x}{4}$

$\\ \tt\hookrightarrow -3x=4y-36$

$\\ \tt\hookrightarrow x=\dfrac{-4}{3}y+12$

Now

$\\ \tt\hookrightarrow f^{-1}x=\dfrac{-4}{3}x+12$

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GalinKa [24]

Answer:

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Step-by-step explanation:

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The sum of the zeroes is 2=5-3 and their product is -15=-3*5, so we can factorise by (x-5)(x+3), which gives.

$f(x)=(x^2+16)(x^2-2x-15)\\\\=(x^2+16)(x^2+3x-5x-15)\\\\=(x^2+16)(x(x+3)-5(x+3))\\\\=\boxed{(x^2+16)(x+3)(x-5)}$

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