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3 years ago

Write an equation of the line passing through the points (3,5) and (-1. - 15).

Mathematics

2 answers:

fgiga [73]3 years ago

6 0

Answer:

y=20/4x-10

Step-by-step explanation:

(3, 5) (-1, -15)

-15-5/-1-3=20/4x

y=-10

kari74 [83]3 years ago

5 0

Answer:

y = 5x - 10

Step-by-step explanation:

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I will mark as brainliest. Area of a square is 25^m. Find its Perimeter. With working please

77julia77 [94]

Answer:

perimeter = 20 m

Step-by-step explanation:

given the area of the square = 25 m² and

area of a square = s² ( where s is the side length ), then

s² = 25 ( take the square root of both sides )

s = $\sqrt{25}$ = 5 ← length of side

perimeter = 4s = 4 × 5 = 20 m

3 0

3 years ago

Given y=3x-7. When x = 0 what is the value of y

MissTica

Answer:

-7

Step-by-step explanation:

y=3x-7

x=0 ⇒ y= 3*0-7= -7

7 0

3 years ago

The population of a small town in central Florida has shown a linear decline in the years 1992-2000. In 1992 the population was

wlad13 [49]

Answer:

P = -390t +48,000
P = 43,710 in 2003

Step-by-step explanation:

A) We are given two pairs of (t, P): (0, 48000), (8, 44880). We can use these with the 2-point form of the equation of a line:

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

P = (44880 -48000)/(8 -0)(t -0) +48000

P = -3120/8t +48000

P = -390t +48000

B) In 2003, t = 11, so we have ...

P = -390(11) +48000 = 43710

The population in 2003 is predicted to be 43,710.

7 0

3 years ago

Darren wants to estimate the mean age in a population of trees. He'll sample nnn trees and build a 90\%90%90, percent confidence

Alchen [17]

Using the z-distribution, as we have the standard deviation for the population, it is found that the smallest sample size required to obtain the desired margin of error is of 77.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

z is the critical value.

n is the sample size.

$\sigma$ is the standard deviation for the population.

The margin of error is given by:

$M = z\frac{\sigma}{\sqrt{n}}$

In this problem, we have that the parameters are given as follows:

$M = 3, z = 1.645, \sigma = 16$ .

Hence, solving for n, we find the sample size.

$M = z\frac{\sigma}{\sqrt{n}}$

$3 = 1.645\frac{16}{\sqrt{n}}$

$3\sqrt{n} = 1.645 \times 16$

$\sqrt{n} = \frac{1.645 \times 16}{3}$

$(\sqrt{n})^2 = \left(\frac{1.645 \times 16}{3}\right)^2$

$n = 76.97$

Rounding up, the smallest sample size required to obtain the desired margin of error is of 77.

More can be learned about the z-distribution at brainly.com/question/25890103

4 0

1 year ago

Specify three fractions with different denominators that have a LCD of 24 then arrange the fractions in order from least to grea

romanna [79]

We can just guess 20/24, 10 / 24 and 8 / 24

From the least to the greatest:

8/24, 10/24, 20/24

8/24 = 1/3 10/24 = 5/12 20/24 = 5/6

So it is:

1/3, 5/12, 5/6

I hope this helps.

3 0

3 years ago

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