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Julli [10]
3 years ago
7

Write an equation of the line passing through the points (3,5) and (-1. - 15).

Mathematics
2 answers:
fgiga [73]3 years ago
6 0

Answer:

y=20/4x-10

Step-by-step explanation:

(3, 5) (-1, -15)

-15-5/-1-3=20/4x

y=-10

kari74 [83]3 years ago
5 0

Answer:

y = 5x - 10

Step-by-step explanation:

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Monica [59]
To solve for X: First you multiply x and 6 then subtract 21 on both sides and then divide by 6

531 = ( X × 6) + 21
531 = 6X + 21
510 = 6X
85 = X 

Hope this helps :)
4 0
4 years ago
Read 2 more answers
What is the value of the expression? <br><br> 10 – 4 + (80 ÷ 20) y^4
Mariana [72]
Ok so 1st, you do the (80 ÷ 20), then you get
10-4+(4)y^4
then you 10-4
6+(4)y^4
then....
(10)y^4
so then it's 
10y^4
Unless there is a =, but if not it's 10y^4
3 0
4 years ago
A single die is rolled. Find the probability of each of the following events :
IceJOKER [234]

\frac{1}{2} and \frac{1}{3}

There are 6 possible outcomes when rolling a die, 1, 2, 3, 4 , 5, 6

A

numbers less than 4 are 1, 2, 3

P( number less than 4 ) = \frac{3}{6} = \frac{1}{2}

B

numbers greater than 4 are 5, 6

P( number greater than 4 ) = \frac{2}{6} = \frac{1}{3}


7 0
3 years ago
X is a real number greater than or equal to 5.5. What are the possible numbers for X?
SOVA2 [1]
X <span>≥ 5.5.

So it can be anywhere from 5.5 to </span><span>∞ (infinity)

P.S this symbol </span>∞ <span>is sometimes called a </span>lemniscate
7 0
4 years ago
Your firm wants to investigate how much money the typical tourist will spend on their next visit to New York? How many tourists
dimaraw [331]

Answer:

n=(\frac{2.58(59)}{20})^2 =57.93

And if we round up the answer we see that the value of n to ensure the margin of error required \pm=20 $ is n=58.

C) 58

Step-by-step explanation:

Assuming this :"Your firm wants to investigate how much money the typical tourist will spend on their next visit to New York. How many tourists should be included in your sample if you want to be 99% confident that the sample mean is within $20 from the population mean? From previous studies, we know that the standard deviation is $59."

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

X \sim N(\mu, \sigma=59)

We know that the margin of error for a confidence interval is given by:

Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The next step would be find the value of \z_{\alpha/2}, \alpha=1-0.99=.01 and \alpha/2=0.005

Using the normal standard table, excel or a calculator we see that:

z_{\alpha/2}=2.58

If we solve for n from formula (1) we got:

\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}

n=(\frac{z_{\alpha/2} \sigma}{Me})^2

And we have everything to replace into the formula:

n=(\frac{2.58(59)}{20})^2 =57.93

And if we round up the answer we see that the value of n to ensure the margin of error required \pm=20 $ is n=58.

C) 58

6 0
3 years ago
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