It is always negative, because it keeps going down on the number line. Say it is negative 8 minus 5, it would be negative 13, because it adds to the negatives, so it would go deeper into the negatives.
Answer: 
Step-by-step explanation:
By the negative exponent rule, you have that:

By the exponents properties, you know that:

Therefore, you can rewrite the left side of the equation has following:

Descompose 32 and 8 into its prime factors:

Rewrite:

Then:

As the base are equal, then:

Solve for x:

4000(1.05)⁴=$4862.03
6000(1+ .08/2)^35(2)=$93429.71
15450(.86)³=$9827.07
12 inches go into one foot, so we can calculate the volume of the tank in inches to make the calculations that follow easier. Therefore, to calculate the volume of the tank, we use length x breadth x height = 4 x 2 x 2 = 16 square feet x 12 for square inches = 192 square inches.
Every 12 square inches Joseph can fit a one inch fish. The fish that he has are 3 inches long, therefore he can only fit one fish every 36 square inches.
That means that if we take the total volume of the tank and divide it by the space that a 3 inch fish will take up, we are left with 192/36 = 5.3 fish.
You cannot have a third of a fish, so we round off to the nearest whole number, and we determine that Joseph can put 5 fish in his new aquarium.