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fiasKO [112]
3 years ago
8

Thanks + BRAINLIST Need correct answer ASAP

Physics
1 answer:
aliina [53]3 years ago
5 0

Answer:

The options are not shown, so it is kinda hard to give you the exact answer.

But i can try to give a general explanation on the topic.

Interference happens when two waves interact between them. We usually use waves with the same wavelength and same phase.

There are two "main" types of interference:

Destructive interference: Happens when the peak of one wave and the trough of the other wave happen in the same place, then when we add these waves, we have a subtraction, and then the amplitude of the resultant wave is smaller than the amplitudes of the original waves (if both initial waves have the same amplitude, then the amplitude of the resultant wave in that position is zero).

Constructive interference: Similar to the previous case, but now the two waves have the peaks or toughs in the same position, then when we add the waves, we have an addition in the amplitude, then the amplitude of the resultant wave will be larger than the amplitudes of the initial waves.

Then if you are looking for constructive interference, you need to look for an option where the peaks of the waves coincide. For example, in the top image we can see, at the top, a wave with an amplitude of 2 units.

And at the bottom a wave with an amplitude of 1 unit.

We also can see that the peaks (and the tough) are in the same place, then we will have constructive interference. Then the amplitude of the resultant wave will be equal to the sum of the amplitudes of the initial waves (2 and 1)

Then the amplitude of the resultant wave is 2 units + 1 unit = 3 units.

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When you are in the way of a moving object and a collision is sure to occur, you are better off decreasing its momentum over …?
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Michelle recently started selling her invention: A bed that looks like it floats in mid-air. The bed is actually suspended by ma
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While driving, your car has an initial position of 3.2 m, an initial velocity of -8.4 m/s, and
KIM [24]

Answer:

The position of the car at t = 1.5 s is at -8.1625 meters

Explanation:

The initial position of the car is 3.2 meters

The initial velocity is -8.4 m/s

The constant acceleration is 1.1 m/s²

We need to find the final position of the car at the time t = 1.5 seconds

The displacement <em>s</em> = final position - initial position

s=ut+\frac{1}{2}at^{2}, where <em>u</em> is the initial velocity, <em>a</em> is the

constant acceleration and <em>t</em> is the time

So we can find the final velocity by using the rule:

final position - initial position = ut+\frac{1}{2}at^{2}

initial position = 3.2 meters , u = -8.4 m/s , a = 1.1 ²m/s , t = 1.5 s

Substitute these values in the rule

final position - 3.2 = (-8.4)(1.5)+\frac{1}{2}(1.1)(1.5)^{2}

final position - 3.2 = -12.6 + 1.2375

final position - 3.2 = -11.3625

add 3.2 for both sides

final position = -8.1625

<em>That means the car is at 8.1625 meters in opposite direction</em>

<em>The position of the car at t = 1.5 s is at -8.1625 meters </em>

4 0
3 years ago
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