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irinina [24]
3 years ago
9

Sonar is the detection of sound waves reflected off boundaries in water. a region of warm water in a cold lake can produce a ref

lection, as can the bottom of the lake. which would you expect to produce the stronger echo? explain.
Physics
2 answers:
kirill [66]3 years ago
5 0
The stronger echo will originate from the bottom and between the lake since the sound will bounce back harder as the bottom of the lake is solid. Unlike the boundary between the cold and warm water.
svetlana [45]3 years ago
4 0

The echo will be stronger when originated from the bottom of the lake.

Explanation

Echo is created when sound waves get reflected due to difference in the densities of the medium.

As we know that SONAR technique works on the detection of the echo strength to navigate, to determine the thickness of any object in water and also to measure the depth of the water bodies.

A region of warm water and cold water will create very negligible echo as there is no object which can resist the penetration of sound waves in this region.

But the sound waves will get reflected when hits the solid object or the bottom of the lake.

As the bottom of the lake is made up of solid, the sound waves will not be able to penetrate the bottom layer.

This will lead to reflection of sound waves creating echo of stronger energy.

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I hope this helps!
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Explanation:

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Assignments
sladkih [1.3K]

Hello there!

I hope you and your family are staying safe and healthy during this unprecendented time.

A) What is the work done?

Answer: We need to use the formula

w=-F_f(d)

w=-(35)(20)

w=-700J

B) What is the work done on the cart by the gravitational force?  

Alright, we know that the gravitional force is perpendicular to the diplacement. Therefore, we gonna use the following formula:

w=Fdcos90

w=0

C) What is the work done on the cart by the shopper?

This is the easier part, since we already know that the work done by the shopper is the same as the work done by the friction force

W shopper + W friction = 0\\W shopper = W-friction \\W shopper = 700J

D) Find the force the shopper exerts, using energy considerations.

F_f+Fcos25=0\\-35+Fcos25=0\\F=38.6N

E) What is the total work done?

You just need to add them:

w=wshopper+wfriction\\w=0

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Two positive charges of 6 µC are separated by a distance of 50 cm in air. What is the electric field strength at the midpoint of
attashe74 [19]

Answer:

The electric field strength at the midpoint of the line joining the charges is zero (0)

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Given that the two charges are both positive (same charge) and are equal in magnitude that is 6uC. The electric field strength at the midpoint of the line joining the two charges will be equal and opposite in magnitude, therefore they will cancel each other out and the electric field strength at this point will be equal to zero.

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