1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irinina [24]
3 years ago
9

Sonar is the detection of sound waves reflected off boundaries in water. a region of warm water in a cold lake can produce a ref

lection, as can the bottom of the lake. which would you expect to produce the stronger echo? explain.
Physics
2 answers:
kirill [66]3 years ago
5 0
The stronger echo will originate from the bottom and between the lake since the sound will bounce back harder as the bottom of the lake is solid. Unlike the boundary between the cold and warm water.
svetlana [45]3 years ago
4 0

The echo will be stronger when originated from the bottom of the lake.

Explanation

Echo is created when sound waves get reflected due to difference in the densities of the medium.

As we know that SONAR technique works on the detection of the echo strength to navigate, to determine the thickness of any object in water and also to measure the depth of the water bodies.

A region of warm water and cold water will create very negligible echo as there is no object which can resist the penetration of sound waves in this region.

But the sound waves will get reflected when hits the solid object or the bottom of the lake.

As the bottom of the lake is made up of solid, the sound waves will not be able to penetrate the bottom layer.

This will lead to reflection of sound waves creating echo of stronger energy.

You might be interested in
The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the pla
Rama09 [41]
Please elaborate more on your question so I can help you
7 0
2 years ago
If a hot steel tool of 1200°C was put in a bucket to cool and the bucket contained 15L of water of 15°C, and the water temperatu
Mashcka [7]

3.6 kg.

<h3>Explanation</h3>

How much heat does the hot steel tool release?

This value is the same as the amount of heat that the 15 liters of water has absorbed.

Temperature change of water:

\Delta T = T_2 - T_1= 48\; \textdegree{\text{C}}- 15\; \textdegree{\text{C}} = 33 \; \textdegree{\text{C}}.

Volume of water:

V = 15 \; \text{L} = 15 \; \text{dm}^{3} = 15 \times 10^{3} \; \text{cm}^{3}.

Mass of water:

m = \rho \cdot V = 1.00 \; \text{g} \cdot \text{cm}^{-3} \times 15 \times 10^{3} \; \text{cm}^{3} = 15 \times 10^{3} \; \text{g}.

Amount of heat that the 15 L water absorbed:

Q = c\cdot m \cdot \Delta T = 4.18 \; \text{J} \cdot \text{g}^{-1} \cdot \textdegree{\text{C}}^{-1} \times 15 \times 10^{3} \; \text{g} \times 33 \; \textdegree{\text{C}} = 2.06910 \times 10^{6}\; \text{J}.

What's the mass of the hot steel tool?

The specific heat of carbon steel is 0.49 \; \text{J} \cdot \text{g}^{-1} \cdot \textdegree{\text{C}}^{-1}.

The amount of heat that the tool has lost is the same as the amount of heat the 15 L of water absorbed. In other words,

Q(\text{absorbed}) = Q(\text{released}) =2.06910 \times 10^{6}\; \text{J}.

\Delta T = T_2 - T_1 = 1200\; \textdegree{\text{C}} -{\bf 48}\; \textdegree{\text{C}} = 1152\; \textdegree{\text{C}}.

m = \dfrac{Q}{c\cdot \Delta T} = \dfrac{2.06910 \times 10^{6} \; \text{J}}{0.49\; \text{J} \cdot \text{g}^{-1} \cdot \textdegree{\text{C}}^{-1} \times 1152\; \textdegree{\text{C}}} = 3.6 \times 10^{3} \; \text{g} = 3.6 \; \text{kg}.

4 0
3 years ago
Could someone please help me
BaLLatris [955]

Answer:

the size of the shadow will be smaller due to smaller hands

3 0
3 years ago
What are the factors that affect the weather?​
jarptica [38.1K]

Answer:

temperature, atmosphere pressure,wind, topography, humidity etc

6 0
3 years ago
A 15.0-μF capacitor is charged by a 130.0-V power supply, then disconnected from the power and connected in series with a 0.280-
SVETLANKA909090 [29]

The resonant frequency of a circuit is the frequency \omega_0 at which the equivalent impedance of a circuit is purely real (the imaginary part is null).

Mathematically this frequency is described as

f = \frac{1}{2\pi}(\sqrt{\frac{1}{LC}})

Where

L = Inductance

C = Capacitance

Our values are given as

C = 15*10^{-6}\mu F

L = 0.280*10^{-3}mH

Replacing we have,

f = \frac{1}{2\pi}(\sqrt{\frac{1}{LC}})

f = \frac{1}{2\pi}(\sqrt{\frac{1}{(15*10^{-6})(0.280*10^{-3})}})

f= 2455.81Hz

From this relationship we can also appreciate that the resonance frequency infers the maximum related transfer in the system and that therefore given an input a maximum output is obtained.

For this particular case, the smaller the capacitance and inductance values, the higher the frequency obtained is likely to be.

7 0
3 years ago
Other questions:
  • A ray in oil (n = 1.52) reaches a boundary with water (n = 1.33) at 55.9 deg. Does it reflect internally or refract into the air
    7·1 answer
  • HURRY PLS WILL RATE AND THANKS AND BRAINLIEST
    12·1 answer
  • Which of the following classifications of star temperature is coolest?
    6·2 answers
  • A bird is flying directly toward a stationary bird-watcher and emits a frequency of 1420 Hz. The bird-watcher, however, hears a
    14·1 answer
  • WILL GIVE BRAINLIEST AND 50 POINTS!
    14·2 answers
  • Sam, whose mass is 60 Kg, is riding on a 5.0 kg sled initially traveling at 8.0 m/s. He
    14·1 answer
  • Tyrell is holding a cup of hot cholate in his hands which cause his hand to feel
    11·1 answer
  • Please help asap 100 POINTS and BRAINLIEST to best answer.
    8·2 answers
  • HELPPPPPPPPPPPPPP 70PTS NOT A LIE
    6·2 answers
  • Which Moon position in the lunar cycle would provide the largest difference in ocean tides?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!