W + L = 122
W = 3L + 14
3L + 14 + L = 122
4L + 14 = 122
4L = 122 - 14
4L = 108
L = 108/4
L = 27 <=== they lost 27 games
W = 3L + 14
W = 3(27) + 14
W = 81 + 14
W = 95 <=== they won 95 games
The slope of the line is -1/7, so the perpendicular line has a slope of 7
Answer:
Example:
A bag contains 3 black balls and 5 white balls. Paul picks a ball at random from the bag and replaces it back in the bag. He mixes the balls in the bag and then picks another ball at random from the bag.
a) Construct a probability tree of the problem.
b) Calculate the probability that Paul picks:
i) two black balls
ii) a black ball in his second draw
Solution:
tree diagram
a) Check that the probabilities in the last column add up to 1.
b) i) To find the probability of getting two black balls, first locate the B branch and then follow the second B branch. Since these are independent events we can multiply the probability of each branch.
ii) There are two outcomes where the second ball can be black.
Either (B, B) or (W, B)
From the probability tree diagram, we get:
P(second ball black)
= P(B, B) or P(W, B)
= P(B, B) + P(W, B)
Answer:
I thinks its T (3)
Step-by-step explanation:
Answer:
0.218
Step-by-step explanation:
If x represents student that study more than one day, then the probability of x will be 78.2%. In other words, out of 1000 student, 782 of them will study more than one day while 218 of them only study for one day or less
The question asking for the probability that a randomly selected student did not study more than one day, which negation of X statement. So the answer will be ~X= 100%- 78.2%= 21.8%= 0.218
