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3 years ago

14

The most Stanley can afford to pay per year in mortgage payments is $12,000, and his credit score is currently 544. According to

the following table for a $150,000 mortgage, by how many points would he need to improve his credit score in order to take a mortgage for $1 50.000?

2 answers:

Shkiper50 [21]3 years ago

6 0

Answer:131

Step-by-step explanation:

iris [78.8K]3 years ago

3 0

Answer:

131 points

Step-by-step explanation:

Apex. Sad nobody came in clutch for me

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a 240 centimeter board is to be cut into two pieces so that the longer piece is twice as long as the shorter piece. find the len

amid [387]

You need two pieces and 1 has to be 2x longer than the other
set x as the smaller piece (easier to always go with the smaller value as x)
the other piece is 2x (double in size)
your equations would be 3x=240>>> x= 60

so smaller piece/ x= 60
bigger piece/ 2x= 120

7 0

4 years ago

Read 2 more answers

Futhe Mathematics<br><img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2

Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

$\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }$

We can write the numerator as ,

$\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }$

Recall the identity ,

$\longrightarrow (a-b)(a+b)=a^2-b^2$

Using this we have ,

$\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}$

Again , as we know that ,

$\longrightarrow sin^2\phi + cos^2\phi = 1$

Therefore we can rewrite it as ,

$\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}$

Again using the first identity mentioned above ,

$\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}$

Or else we can also write it using ,

$\longrightarrow cos2\phi = cos^2\phi - sin^2\phi$

Therefore ,

$\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}$

And we are done !

$\rule{200}{4}$

Additional info :-

<em>D</em><em>e</em><em>r</em><em>i</em><em>v</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>c</em><em>o</em><em>s</em><em>²</em><em>x</em><em> </em><em>-</em><em> </em><em>s</em><em>i</em><em>n</em><em>²</em><em>x</em><em> </em><em>=</em><em> </em><em>c</em><em>o</em><em>s</em><em>2</em><em>x</em><em> </em><em>:</em><em>-</em>

We can rewrite cos 2x as ,

$\longrightarrow cos(x + x )$

As we know that ,

$\longrightarrow cos(y + z )= cosy.cosz - siny.sinz$

So that ,

$\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)$

On simplifying,

$\longrightarrow cos(x+x) = cos^2x - sin^2x$

Hence,

$\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}$

$\rule{200}{4}$

7 0

3 years ago

Statistics question about random probability Cheese pastureized or Raw MilkA cheese can be classified as either raw-milk or past

blsea [12.9K]

Answer:

(a) Two cheeses are chosen at random. the probability that both cheeses are pasteurized is Pr(PP) = 0.82 x 0.82 = 0.6724 to 4 decimal places)

(b) Four cheeses are chosen at random. The probability that all four cheeses are pasteurized is Pr(PPPP) = 0.82 x 0.82 x 0.82 x 0.82 = 0.4521 to 4 decimal places

(c) What is the probability that at least one of four randomly selected cheeses is raw-milk is Pr(RPPP) Or Pr(RRPP) Or Pr(RRRP) Or Pr(RRRR)

= 0.1269 to 4 decimal places

It would not be unusual that at least one of four randomly selected cheeses is raw-milk, because the probability have a value between 0 and 1

Step-by-step explanation:

If is given that 80% of the cheese is classified as pasteurized.

It then implies that 20% of the cheese is classified as Raw-milk

Probability of pasteurized cheese is 0.82(Denoted by Pr(P))

Probability of raw-milk cheese is 0.18(Denoted as Pr(R))

(a) Two cheeses are chosen at random. the probability that both cheeses are pasteurized is Pr(PP) = 0.82 x 0.82 = 0.6724 to 4 decimal places)

(b) Four cheeses are chosen at random. The probability that all four cheeses are pasteurized is Pr(PPPP) = 0.82 x 0.82 x 0.82 x 0.82 = 0.4521 to 4 decimal places

(c) What is the probability that at least one of four randomly selected cheeses is raw-milk is Pr(RPPP) + Pr(RRPP) + Pr(RRRP) + Pr(RRRR)

(0.18 x 0.82 x 0.82 x 0.82) + (0.18 x 0.18 x 0.82 x 0.82) + (0.18 x 0.18 x 0.18 x 0.82) + (0.18 x 0.18 x 0.18 x 0.18) = 0.1269 to 4 decimal places

3 0

3 years ago

Find the value of x and then the measure of Arc XYZ and Arc XZ. Show work on a piece of paper.

Westkost [7]

<u>Given</u>:

The measure of arc XY is (31x)°

The measure of arc YZ is (35x - 16)°

We need to determine the value of x, measure of arc XYZ and arc XZ.

<u>Value of x:</u>

From the figure, it is obvious that the arcs XY and YZ are congruent.

Thus, we have;

$31x=35x-16$

Subtracting both sides by 35x, we have;

$-4x=-16$

$x=4$

Thus, the value of x is 4.

<u>Measure of arc XYZ:</u>

The measure of arc XYZ is given by

$m \widehat{XYZ}=m \widehat{XY}+m \widehat{YZ}$

The measure of arc XY is given by

$m \widehat{X Y}=31(4)=124^{\circ}$

The measure of arc YZ is given by

$m \widehat{Y Z}=35(4)-16=124^{\circ}$

Hence, the measure of arc XYZ is given by

$m \widehat{XYZ}=124^{\circ}+124^{\circ}=248^{\circ}$

Therefore, the measure of arc XYZ is 248°

<u>Measure of arc XZ:</u>

The measure of arc XZ is given by

$m \widehat{XZ}=360^{\circ}-m \widehat{XYZ}$

Substituting the values, we have;

$m \widehat{XZ}=360^{\circ}-248^{\circ}$

$m \widehat{XZ}=112^{\circ}$

Thus, the measure of arc XZ is 112°

5 0

3 years ago

Solve the following <br><br><br> C^2-14=5c

kipiarov [429]

Answer:

c = - 2, c = 7

Step-by-step explanation:

Given

c² - 14 = 5c ( subtract 5c from both sides )

c² - 5c - 14 = 0 ← in standard form

To factorise the quadratic

Consider the factors of the constant term (- 14) which sum to give the coefficient of the c- term (- 5)

The factors are - 7 and + 2, since

- 7 × 2 = - 14 and - 7 + 2 = - 5, hence

(c - 7)(c + 2) = 0

Equate each factor to zero and solve for c

c - 7 = 0 ⇒ c = 7

c + 2 = 0 ⇒ c = - 2

8 0

3 years ago