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Vikentia [17]
3 years ago
9

What is Type of compound of ICI

Chemistry
2 answers:
valentina_108 [34]3 years ago
8 0

Answer:

ICI 204448 hydrochloride | C23H27Cl3N2O4 | CID 129407 - structure, chemical names, physical and chemical properties, classification, patents, literature, etc...

hope this helps!! have an amazing day <3

Kisachek [45]3 years ago
4 0

Answer:

ICI-118,551 is a selective β2 adrenergic receptor (adrenoreceptor) antagonist or beta blocker. ICI binds to the β2 subtype with at least 100 times greater affinity than β1 or β3, the two other known subtypes of the beta adrenoceptor.

Explanation:

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What is the charge of a cation?
kolezko [41]

Answer:

A cation has more protons than electrons, consequently giving it a net positive charge. For a cation to form, one or more electrons must be lost, typically pulled away by atoms with a stronger affinity for them.

Were i found my answer: Cation vs Anion: Definition, Chart and the Periodic Table

Explanation:

5 0
3 years ago
What is the molality of a solution made by dissolving 15.20 g of i2 in 1.33 mol of diethyl ether, (ch3ch2)2o?
Paraphin [41]
The  molarity   of solution  made  by  dissolving  15.20g  of i2  in 1.33 mol  of diethyl ether (CH3CH2)2O  is    =0.6M

   calculation

molarity  =moles of solute/  Kg of the  solvent

mole  of the solute  (i2)  =  mass /molar mass
the molar mass of i2 = 126.9 x2 = 253.8 g/mol

moles is therefore=  15.2 g/253.8 g/mol  =  0.06  moles


calculate the Kg of solvent  (CH3CH2)2O
mass =  moles  x  molar mass
molar mass  of  (CH3CH2)2O= 74 g/mol

mass  is therefore = 1.33 moles  x  74 g/mol =  98.42 grams
in Kg = 98.42 /1000 =0.09842  Kg

molarity  is therefore = 0.06/0.09842 = 0.6 M

3 0
4 years ago
If I add 475mL of water to 75.0mL of a 0.315M NaOH solution, what will the molarity of the diluted solution be?
pantera1 [17]
Answer is: <span>the molarity of the diluted solution 0,043 M.
</span>V(NaOH) = 75 mL ÷ 1000 mL/L = 0,075 L.
c(NaOH) = 0,315 M = 0,315 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,075 L · 0,315 mol/L.
n(NaOH) = 0,023625 mol.
V(solution) = 0,475 L + 0,75 L.
c(solution) = 0,023625 mol ÷ 0,550 L.
c(solution) = 0,043 mol/L.
5 0
4 years ago
Choose the FALSE statement.
Mariana [72]

Answer:

C. The half-life of C-14 is about 40,000 years.

Explanation:

The only false statement from the options is that the half-life of C-14 is 40,000yrs.

The half-life of an isotope is the time it takes for half of a radioactive material to decay to half of its original amount. C-14 has an half-life of 5730yrs. This implies that during every 5730yrs, C-14 will reduce to half of its initial amount.

  • All living organisms contain both stable C-12 and the unstable isotope of C-14
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5 0
3 years ago
Which is an example of an organism? A. an octopus B. sand granules C. water D. the colors of a feather
denpristay [2]
A. An octopus

An organism is an individual animal, plant, or single-celled life form.

The octopus is the only living thing listed so that is why it is the example of an organism
5 0
3 years ago
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