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4 years ago

12

Why does graphite and diamond sublime?

1 answer:

GREYUIT [131]4 years ago

8 0

Answer:

The intermolecular bonding in the solid is van der Waals dispersion forces. That means that it will have a lower melting point than diamond or graphite where you have giant covalent bonding. In fact C60 sublimes at 800 K (527°C). Diamond and graphite sublime at around 4000 K.

Explanation:

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How does octect law work?

zlopas [31]

Octet law states that every atom tries to attain a octet valence shell (8 electrons in their valence shell) to attain a more stable state. For attaining this they form bonds(covalent,ionic etc) with other atoms. Please ask if you any more doubt on this, I'll try to help

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3 years ago

Which atmospheric gas is used by plants and given off by animals

elena-14-01-66 [18.8K]

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3 years ago

A chemist reacted 17.25 grams of sodium metal with an excess amount of chlorine gas. The chemical reaction that occurred is show

Afina-wow [57]

<u>Answer:</u> The actual yield of the product is 38.57 g

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

We are given:

Given mass of Na = 17.25 g

Molar mass of Na = 23 g/mol

Putting values in equation 1, we get:

$\text{Moles of Na}=\frac{17.25g}{23g/mol}=0.75mol$

For the given chemical reaction:

$2Na+Cl_2\rightarrow 2NaCl$

By stoichiometry of the reaction:

2 moles of Na produces 2 moles of NaCl

So, 0.75 moles of Na will produce = $\frac{2}{2}\times 0.75=0.75mol$ of NaCl

We know, molar mass of $NaCl$ = 58.44 g/mol

Putting values in above equation, we get:

$\text{Mass of NaCl}=(0.75mol\times 58.44g/mol)=43.83g$

The percent yield of a reaction is calculated by using an equation:

$\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100$ ......(1)

Given values:

Percent yield of the product = 88 %

Theoretical value of the product = 43.83 g

Plugging values in equation 1:

$88\% =\frac{\text{Actual yield}}{43.83g}\times 100\\\\\text{Actual yield}=\frac{88\times 43.83}{100}=38.57g$

Hence, the actual yield of the product is 38.57 g

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3 years ago

A student wishes to prepare 25mL of 0.1M NaOH from 6M NaOH.

liraira [26]

Answer:

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Explanation:

Look at the charges and add them up

Na(OH) Na(OH)

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Answer:

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Explanation:

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3 years ago

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