Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
The answer should be n=-8
If g is the gallons of gas, and the truck holds up to 20 gallons, then g can be anything from 0 to 20.
If there is zero gallons of gas (g = 0) then the truck will travel zero miles because M(0) = 17(0) = 0.
The max miles depends on the max gallons of gas, so the miles possible with 20 gallons is M(20) = 17(20) = 340.
So, g ranges from 0 to 20 and M(g) ranges from 0 to 340.
Therefore your answer is the last option.
I hope this helps you
-( 3.5+1/3) ÷ 2.4+3/4
- 16/3 ÷ 11/4
-16/3 × 4/11
- 64 / 33
- 1 31 /33
A) given that in 2019 you were among the 21.11% of the best students in the class, in that year you had the higher percentile ranking, and B) the measure of average that would be the most meaningful is the median.
Given that your class rank in 2018 was 89 out of 360 students, while in 2019 your class rank was 95 out of 450 students, to determine A) in which year did you have the higher percentile ranking, and B) if you had the data on the cumulative GPA of each student at the end of the spring semester in 2018, which measure of average would be the most meaningful - mean, median or mode -, the following calculation should be performed:
- 360 = 100
- 89 = X
- 89 x 100/360 = X
- 24.72 = X
- 450 = 100
- 95 = X
- 95 x 100/450 = X
- 21.11 = X
Therefore, A) given that in 2019 you were among the 21.11% of the best students in the class, in that year you had the higher percentile ranking, and B) the measure of average that would be the most meaningful is the median.
Learn more about maths in brainly.com/question/25748895
