Adding what rational expressions?
Answer:
a₂ = - 28.5
Step-by-step explanation:
the nth term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
here a₁ = - 45 and given a₃ = - 12 , then
a₁ + 2d = - 12 , that is
- 45 + 2d = - 12 ( add 45 to both sides )
2d = 33 ( divide both sides by 2 )
d = 16.5
Then
a₂ = a₁ + d = - 45 + 16.5 = - 28.5
Answer:
![g(x) = 6(2)^{x -8}+ 4](https://tex.z-dn.net/?f=g%28x%29%20%3D%206%282%29%5E%7Bx%20-8%7D%2B%20%204)
Step-by-step explanation:
Given
![f(x) = 6(2)^{x - 1}+ 4](https://tex.z-dn.net/?f=f%28x%29%20%3D%206%282%29%5E%7Bx%20-%201%7D%2B%20%204)
Required
Find g(x)
From the question, f(x) is translated 7 units left;
The rule of translation is: ![(x,y) \to (x-7,y)](https://tex.z-dn.net/?f=%28x%2Cy%29%20%5Cto%20%28x-7%2Cy%29)
So, we have:
![g(x) = f(x - 7)](https://tex.z-dn.net/?f=g%28x%29%20%3D%20f%28x%20-%207%29)
![g(x) = 6(2)^{x -7- 1}+ 4](https://tex.z-dn.net/?f=g%28x%29%20%3D%206%282%29%5E%7Bx%20-7-%201%7D%2B%20%204)
![g(x) = 6(2)^{x -8}+ 4](https://tex.z-dn.net/?f=g%28x%29%20%3D%206%282%29%5E%7Bx%20-8%7D%2B%20%204)
Answer:
10
Step-by-step explanation:
![x=0 \implies x\in \{-15, -12, 0, 10\} \\ \\ \therefore f(0)=11-|0-1|=10](https://tex.z-dn.net/?f=x%3D0%20%5Cimplies%20x%5Cin%20%5C%7B-15%2C%20-12%2C%200%2C%2010%5C%7D%20%5C%5C%20%5C%5C%20%5Ctherefore%20f%280%29%3D11-%7C0-1%7C%3D10)
Answer:
a 6 - 3x , hope I helped. have a nice day