Respuesta:
h = V / 15
Explicación paso a paso:
El volumen de un prisma rectangular se calcula usando la relación:
Largo ancho alto
Donde, largo y ancho son la dimensión de la base
Por eso,
Volumen = Base * altura
Volumen = (5 cm * 3 cm) * altura
De la pregunta, no se da el volumen, por lo tanto, tomamos el volumen como V en otro para calcular la altura, h
V = 15h
Divide ambos lados entre 15
V / 15 = 15h / 15
V / 15 = h
If he has 6 left over it has to be 288 cubic feet so the dimensions could be 12x12x2
The function f(x) = 2|x – 2| + 6 has a vertex at (2, 6) option second is correct.
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have a function that has vertex at (2, 6)
The options are:
f(x) = 2|x – 2| – 6
f(x) = 2|x – 2| + 6
f(x) = 2|x + 2| + 6
f(x) = 2|x + 2| – 6
As we know the vertex form of a quadratic function is given by:
f(x) = a(x - h)² + k
Similarly, mod function can be expressed as:
m(x) = a|x - h| + k
Here (h, k) is the vertex of a function.
In the function:
f(x) = 2|x – 2| + 6
The vertex of the function is (2, 6)
Thus, the function f(x) = 2|x – 2| + 6 has a vertex at (2, 6) option second is correct.
Learn more about the function here:
brainly.com/question/5245372
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He has 2 1/8 cups more brown rice than white rice
Given:
Vertices of a square are A(-4,6), B(5,6) C(4,-2), and D(-5,-2).
To find:
The intersection of the diagonals of square ABCD.
Solution:
We know that diagonals of a square always bisect each other. It means intersection of the diagonals of square is the midpoint of diagonals.
In the square ABCD, AC and BD are two diagonals. So, intersection of the diagonals is the midpoint of both AC and BD.
We can find midpoint of either AC or BD because both will result the same.
Midpoint of A(-4,6) and C(4,-2) is
![Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)](https://tex.z-dn.net/?f=Midpoint%3D%5Cleft%28%5Cdfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%5Cdfrac%7By_1%2By_2%7D%7B2%7D%5Cright%29)
![Midpoint=\left(\dfrac{-4+4}{2},\dfrac{6+(-2)}{2}\right)](https://tex.z-dn.net/?f=Midpoint%3D%5Cleft%28%5Cdfrac%7B-4%2B4%7D%7B2%7D%2C%5Cdfrac%7B6%2B%28-2%29%7D%7B2%7D%5Cright%29)
![Midpoint=\left(\dfrac{0}{2},\dfrac{6-2}{2}\right)](https://tex.z-dn.net/?f=Midpoint%3D%5Cleft%28%5Cdfrac%7B0%7D%7B2%7D%2C%5Cdfrac%7B6-2%7D%7B2%7D%5Cright%29)
![Midpoint=\left(\dfrac{0}{2},\dfrac{4}{2}\right)](https://tex.z-dn.net/?f=Midpoint%3D%5Cleft%28%5Cdfrac%7B0%7D%7B2%7D%2C%5Cdfrac%7B4%7D%7B2%7D%5Cright%29)
![Midpoint=\left(0,2\right)](https://tex.z-dn.net/?f=Midpoint%3D%5Cleft%280%2C2%5Cright%29)
Therefore, the intersection of the diagonals of square ABCD is (0,2).