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3 years ago

please help me on this I'm struggling on this thanks for your helping of you answer.please show your work:-)

Mathematics

2 answers:

Tju [1.3M]3 years ago

7 0

A fraction that represents the same value when both the numerator and the denominator are multiplied by the same number is known as an equivalent fraction.

Part A: 5/20

Equivalent fractions - 5/20,6/24,7/28

Percent :

5/20

Simplify = 1/4

The numerator is the top part of a fraction, and the denominator is the bottom part of a fraction. To convert to decimal divide the numerator and denominator. 

= 1 ÷ 4

Decimal = 0.25

0.25 x 100 = 25%

Part B: 9/20

Equivalent fractions - 18/40,27/60,36/80

Percent:

Fraction = 9/20

The numerator is the top part of a fraction, and the denominator is the bottom part of a fraction. To convert to decimal divide the numerator and denominator.

= 9 ÷ 20

Decimal = 0.45

0.45 x 100 = 45%

Part C: 9/6

Equivalent fractions -12/8,15/10,18/12

Percent: 9/6

Simplify = 3/2

The numerator is the top part of a fraction, and the denominator is the bottom part of a fraction. To convert to decimal divide the numerator and denominator.

= 3 ÷ 2

Decimal = 1.5

1.5 x 100 = 150%

PilotLPTM [1.2K]3 years ago

6 0

A. is 1/4 so that would be 25%
sorry thats all i know

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122.5

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Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The thre

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Answer:

The area function is

$A=\frac{135}{2}x-\frac{9}{2}x^2$ .

The domain and range of A is $(0,15m)$ and $(0, 253.125 m^2]$ .

Step-by-step explanation:

The given length of fencing is $90 m$ .

Let the length and width of each pen be $x$ and $y$ respectively as shown in the figure.

As there are 3 pens, so, the total area,

$A= 3 xy \;\cdots (i)$

From the figure the total length of fencing is $6x+4y$ .

Here, for a significant area for the animals, $x>0$ as well as $y>0$ as $x$ and $y$ are the sides of ben.

From the given value:

$6x+4y=90\;\cdots (ii)$

$\Rightarrow y=\frac {45}{2}-\frac{3x}{2}$

Now, from equation (i)

$A=3x\left(\frac {45}{2}-\frac{3x}{2}\right)$

$\Rightarrow A=\frac{135}{2}x-\frac{9}{2}x^2\;\cdots (iii)$

This is the required area function in the terms of variable $x$ .

For the domain of area function, from equation (ii)

$x=15-\frac{2y}{3}$

$\Rightarrow x$ [as y>0]

So, the domain of area function is $(0,15m)$ .

For the range of area function:

As $x \rightarrow 0$ or $y\rightarrow 0$ , then $A\rightarrow 0$ [from equation (i)]

$\Rightarrow A>0$

Now, differentiate the area function with respect to $x$ .

$\frac {dA}{dx}=\frac{135}{2}-9x$

Equate $\frac {dA}{dx}$ to zero to get the extremum point.

$\frac {dA}{dx}=0$

$\Rightarrow \frac{135}{2}-9x=0$

$\Rightarrow x=\frac{15}{2}$

Check this point by double differentiation

$\frac {d^2A}{dx^2}=-9$

As, $\frac {d^2A}{dx^2}$ , so, point $x=\frac{15}{2}$ is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

$A=\frac{135}{2}\times \frac {15}{2}-\frac{9}{2}\times \left(\frac {15}{2}\right)^2$

$\Rightarrow A=253.125 m^2$

Hence, the range of area function is $(0, 253.125 m^2]$ .

4 0

3 years ago

o-na [289]

Answer
D
Hope this help you?

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2 years ago

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Answer:

Step-by-step explanation:

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