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lilavasa [31]
3 years ago
14

How many intersections are there of the graphs of the equations below? One-halfx + 5y = 6

Mathematics
1 answer:
andre [41]3 years ago
8 0

Answer:

Just go to calulator soup. It’s a website. It will help

Step-by-step explanation:

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A polygon has an area of 225 square meters. If the area is tripled, how does each side length change?
krok68 [10]
Let me tell you the process so that you get to the answer
Remember first that the area of a regular polygon with x sides has  each of them a length which can be represented by y 

<span>A = 1/4 * xy^2 * Cot(180/x) </span>
<span>The purpose is to solve for y, so we get </span>
<span>y^2 = 4A/(xCot(180/x)) </span>
<span>y = √(4A/(xCot(180/x)))

The thing we need to change is A in the previous formula and with that we can use the equaation to be a constant. This could be represented by Z
</span><span>Z = √(4/(xCot(180/x)))
so
</span><span>Y = Z√A 
</span><span>If we increase area by a factor s, y increases by a factor of √x.
</span>So if you want to know the triple then you need to increase it by <span> √3 </span> <span>  </span>
3 0
2 years ago
The diagram shows a sketch of a survey done by a civil engineering student .Find the value of x,giving your answer correct to 1
Hatshy [7]

You can do this by drawing one line through parallel to PQS to meet RQ at T

Now calculate length of RT:-

cos 70 = RT / 70 giving RT = 23.94m

sin 70 = ST/70 giving ST = 65.78 m

draw a line from S perpendicular to PQ to meet PQ at U.

PU = 110 - 65.78 = 44.22 m

tan 50 = SU / 44.22 giving SU = 52.70 m

TQ = SU = 52.70 m

So x = TQ + RT = 52.70 + 23.94 = 76.6 m to 1 dec place.

7 0
2 years ago
Find the perimeter of the following polygon. Be sure to include the correct unit in your answer.
slava [35]

Answer:

48

Step-by-step explanation:

All you got to do is add all of them together

8 0
3 years ago
I need h e l p !!!!!!!!!!!!!!!!
Strike441 [17]

Answer:

  • 3/ 23765

Step-by-step explanation:

There are 12 E's out of 100 tiles.

Tiles are not replaced.

<u>The probability of each of first 4 E's is:</u>

  • The first E ⇒ P(E) = 12/100 = 3/25
  • The second E ⇒ P(E) = 11/99 = 1/9
  • The third E ⇒ P(E) = 10/98 = 5/49
  • The fourth E ⇒ P(E) = 9/97

<u>The probability of 4 E's is:</u>

  • P(4 E's) = 3/25*1/9*5/49*9/97 = 3 / (5*49*97) = 3 / 23765

3 0
3 years ago
a) The quadratic 3x^2-12x-11 can be written in the form 3(x+a)^2+b. Find the values of a and b. b) Given that the solutions of t
LenKa [72]

Answer:

Step-by-step explanation:

a) 3x^2-12x-11=3*x^2-3*2*2*x+3*4-23=3*(x^2-2*2x+2^2)-23=3*(x-2)^2-23

so  a= -2 ,b= -23

b) x1=[12+V(12^2-4*3* -11)]/6=12/6+V(144+132)/6=2+2/6V69=2+1/3V69=

2+V69/9=2+V23/3

c=2, d= 23/3

5 0
2 years ago
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