Let me tell you the process so that you get to the answer
Remember first that the area of a regular polygon with x sides has each of them a length which can be represented by y
<span>A = 1/4 * xy^2 * Cot(180/x) </span>
<span>The purpose is to solve for y, so we get </span>
<span>y^2 = 4A/(xCot(180/x)) </span>
<span>y = √(4A/(xCot(180/x)))
The thing we need to change is A in the previous formula and with that we can use the equaation to be a constant. This could be represented by Z
</span><span>Z = √(4/(xCot(180/x)))
so
</span><span>Y = Z√A
</span><span>If we increase area by a factor s, y increases by a factor of √x.
</span>So if you want to know the triple then you need to increase it by <span> √3 </span> <span> </span>
You can do this by drawing one line through parallel to PQS to meet RQ at T
Now calculate length of RT:-
cos 70 = RT / 70 giving RT = 23.94m
sin 70 = ST/70 giving ST = 65.78 m
draw a line from S perpendicular to PQ to meet PQ at U.
PU = 110 - 65.78 = 44.22 m
tan 50 = SU / 44.22 giving SU = 52.70 m
TQ = SU = 52.70 m
So x = TQ + RT = 52.70 + 23.94 = 76.6 m to 1 dec place.
Answer:
48
Step-by-step explanation:
All you got to do is add all of them together
Answer:
Step-by-step explanation:
There are 12 E's out of 100 tiles.
Tiles are not replaced.
<u>The probability of each of first 4 E's is:</u>
- The first E ⇒ P(E) = 12/100 = 3/25
- The second E ⇒ P(E) = 11/99 = 1/9
- The third E ⇒ P(E) = 10/98 = 5/49
- The fourth E ⇒ P(E) = 9/97
<u>The probability of 4 E's is:</u>
- P(4 E's) = 3/25*1/9*5/49*9/97 = 3 / (5*49*97) = 3 / 23765
Answer:
Step-by-step explanation:
a) 3x^2-12x-11=3*x^2-3*2*2*x+3*4-23=3*(x^2-2*2x+2^2)-23=3*(x-2)^2-23
so a= -2 ,b= -23
b) x1=[12+V(12^2-4*3* -11)]/6=12/6+V(144+132)/6=2+2/6V69=2+1/3V69=
2+V69/9=2+V23/3
c=2, d= 23/3
