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3 years ago

The width of a rectangler figure is 5 units smaller than its length. if its area is 14 units square. find its dimensions

Mathematics

1 answer:

oksano4ka [1.4K]3 years ago

6 0

W = L - 5

A = W.L

14 = (L - 5).L

14 = L² - 5L

L² - 5L -14 =0

(L - 7)(L + 2) = 0 {factorized}

L = 7 / L = -2

In this case L would be equal to 7 because a length of anything can't be a negative number

Therefore, W = 2

Answer : Length = 7 Width = 2

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we can plug x=12

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we can break into two parts

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now, we can find area and then combine them

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we can plug x=14

$A(14)=\int\limits^14_0 f{x} \, dx$

we can break into two parts

$A(14)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx+\int\limits^12_8 f{x} \, dx+\int\limits^14_12 f{x} \, dx$

now, we can find area and then combine them

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