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3 years ago

Can someone help me with this math homework please!

Mathematics

2 answers:

Annette [7]3 years ago

8 0

Answer:

A) Over the interval [-2.5, 0.5], the local maximum is 2

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Hope it helps...

kaheart [24]3 years ago

8 0

Answer:

(A) Over the interval [-2.5, 0.5], the local maximum is 2.

Step-by-step explanation:

"Over the interval [-2.5, 0.5], the local maximum is 2."

Correct. The local maximum is the maximum, or highest point, of the graph in a certain area of interval. In [-2.5, 0.5], the highest point is at the y-value of 2.

"As the x-values go to positive infinity, the function's values go to negative infinity."

Wrong. As the x values go to positive infinity (meaning they go to the right, or positive side of the graph), the function goes up, meaning the function's values go to positive infinity.

"The function is decreasing over the interval (-1, 0.75)."

Wrong. Only from [-1, 0] is where that area of the graph decreases. The other half of it, (0, 0.75), is where the graph increases.

"The function is negative for the interval [-2, 0]."

Wrong. Only from [-1, 0] is the function negative. In the interval [-2, -1], the function is positive.

Hope that helps (●'◡'●)

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Please explain how to do this please show work

marta [7]

Answer:

(x-1)(x+4)

I.e x(x+4)-1(x+4)

Xsquare +4x -x -4

Xsquare +3x -4

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3 years ago

Graph the hyperbola with equation quantity x minus 1 squared divided by 49 minus the quantity of y plus 3 squared divided by 9 e

Sliva [168]

Answer:

See attached diagram

Step-by-step explanation:

You are given the equation of hyperbola

$\dfrac{(x-1)^2}{49}-\dfrac{(y+3)^2}{9}=1$

From this equation,

the center of hyperbola is at point (1,-3);
the real semi-axes $a^2=49\Rightarrow a=7;$
the imaginary semi-axes $b^2=9\Rightarrow b=3.$

Draw two parallel lines x=1 and y=-3 (they intersect at the center of hyperbola), then on horizontal line match two hyperbola's vertices (7 units to the left and 7 units to the right from the center). Then draw two branches of hyperbola (one in negative direction and one in positive direction).

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4 years ago

If you purchase a dozen bagels, you save 10%. If a dozen bagels originally costs $11.50, what is the sale price

ziro4ka [17]

The sale price is $ 10.35

10% of 11.5 is 1.15
(10/100 = x/11.5)

11.5-1.15 = 10.35!

4 0

4 years ago

Given: FPST is a trapezoid, FP=ST, m∠F=45°, PF=8, PS=10 Find: The midsegment MN.

kodGreya [7K]

Answer:

$4\sqrt{2}+10$

Step-by-step explanation:

In trapezoid FPST, FP=ST, then this trapezoid is isosceles, so

$m\angle F=m\angle T=45^{\circ}.$

Draw the height PH. Triangle FPH is right triangle with two angles of measure 45°. This means that FH=HP. By the Pythagorean theorem,

$FH^2+PH^2=PF^2,\\ \\2FH^2=8^2,\\ \\FH^2=32,\\ \\FH=4\sqrt{2}.$

Since trapezoid FPST is isosceles, the base FT hasthe length

$FT=2FH+PS=8\sqrt{2}+10.$

Then the length of the midline is

$MN=\dfrac{FT+PS}{2}=\dfrac{8\sqrt{2}+10+10}{2}=4\sqrt{2}+10.$

8 0

3 years ago

Let σ be portion of the paraboloid z = x 2 + y 2 − 9 lying on and below the xy-plane. Let σ have downward orientation. Let C be

Grace [21]

Answer:

See explaination

Step-by-step explanation:

Stoke theorem proposes that the surface integral of the curl of a function over any surface bounded by a closed path is equal to the line integral of a particular vector function round that path.

The Stoke Theorem can be used if you see a two dimensional region bounded by a closed curve, or if you see a single integral ie a line integral.

See attached file for further solution.

6 0

4 years ago