It would be .98 feet or 11.81 inches
<u>Answer:</u>
He must sell 190 posters make a profit of $300.
<u>Explanation:
</u>
Given:
Base fee= $270
Fee for supplies= $2
Cost of poster=$5
To find:
The number of posters to be sold to get a profit of $300=?
Solution:
Let the number of posters sold be n.
Now, we know that,
profit = selling price – cost price
$ 300 = $ 5 for each poster – ( $ 270 base fee + $ 2 for each poster)
300 = 5 x n – (270 + 2 x n)
300 = 5n – 270 – 2n
5n – 2n = 300 + 270
3n = 570
n = 190
Explanation:
As his uniform is made up of tan or blue pants and a blue or white collared shirt.
So, there are possibly four combinations which are as follows:
- tan pants/blue shirt
- tan pants/white shirt
- blue pants/blue shirt
- blue pants/white shirt
As Benjamin carries an extra piece of white shirt. So, he has a little bit better than 25% chance of wearing his favorite combination.
So,
- Probability of getting tan pants = 2/4 = 1/2
- Probability of getting white shirt = 3/5
The probability of getting both can be computed by simply multiplying 2/4 and 3/5.
So,
- Probability of getting both = 1/2 × 3/5 = 3/10 ⇒ 30%
<em>Keywords: probability, chance</em>
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Is the algebra, if so what type?
<h3>
Answer: B) Median</h3>
The middle vertical line inside the box is the median or the value of Q2. The term "median" is used more often instead of Q2, but your book may use this terminology as well.
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side notes:
* The left and right edges of the box are Q1 and Q3 respectively
* The IQR (interquartile range) is found by subtracting Q3 and Q1
* The min and max are the left and right most edges of the the whiskers, this is assuming there are no outliers
* There is no way to get the mean or mode from a box and whisker plot alone.
* The term "average" is too vague and could refer to mean, median, or mode.
