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Masteriza [31]
3 years ago
9

You finance a $500 car repair completely on credit, you will just pay the minimum payment each month for the next three months.

The APR is 18.99% and the minimum payment each month is 4% of the balance. Determine the finance charge, carry-over balance, and minimum payment required for each of the next two months, and the starting balance for month 2 in the table below.
Mathematics
1 answer:
Cloud [144]3 years ago
6 0

Answer:

Determination of the Finance Charge, Carry-over balance, Minimum Payment for each of the next two months:

Finance Charge:

First month = $7.91

Second month = $7.72

Carry-over balance:

First month = $487.59

Second month = $475.50

Minimum Payment:

First month = $20.32

Second month = $19.81

Starting balance (Carry-over balance + Finance charge):

First month = $507.91

Second month = $495.31

Step-by-step explanation:

a) Data and Calculations:

Credit Finance = $500

APR = 18.99%

Minimum monthly payment = 4% of the balance

Monthly rate of interest = 0.1899/12 = 0.015825

Finance Charge:

First month = $7.91 ($500 * 0.015825)

Second month = $7.72 ($487.59 * 0.015825)

Carry-over balance:

First month = $487.59($507.91 - $20.32)

Second month = $475.50 ($495.31 - $19.81)

Minimum Payment:

First month = $20.32 ($507.91 * 4%)

Second month = $19.81 ($495.31 * 4%)

Starting balance (Carry-over balance + Finance charge):

First month = $507.91 ($500 + $7.91)

Second month = $495.31 ($487.59 + $7.72)

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<h3>4 Answers: A, B, C, D</h3>

=======================================================

Explanation:

f(x) is continuous when x >= 1. The only discontinuity for f(x) is when x = 0, but 0 is not part of this interval.

f(x) is positive for any valid x value in the domain since x^6 is always positive. In general, x^n is positive for all x when n is any even number.

f(x) is decreasing. You can see this through a table of values or through a graph. For anything in the form 1/(x^k), it will be a decreasing function because x^k gets larger, so 1/(x^k) gets smaller, when x goes to infinity.

--------------------

The conditions to use the integral test have been met. So we have to see if \displaystyle \int_1^{\infty}f(x)dx converges or not.

Let's integrate and find out

\displaystyle \int \frac{1}{x^6} dx = \int x^{-6} dx\\\\\\ \displaystyle \int \frac{1}{x^6} dx = \frac{1}{1+(-6)}x^{-6+1}+C\\\\\\ \displaystyle \int \frac{1}{x^6} dx = \frac{1}{-5}x^{-5}+C\\\\\\ \displaystyle \int \frac{1}{x^6} dx = -\frac{1}{5}*\frac{1}{x^5}+C\\\\\\ \displaystyle \int \frac{1}{x^6} dx = -\frac{1}{5x^5}+C\\\\

So we have

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