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denpristay [2]
3 years ago
6

What is an equation of the line that passes through the points (-4, -2) and (8, 1)? Put your answer in fully reduced form.

Mathematics
1 answer:
Alexxx [7]3 years ago
8 0

Answer:

y=1/4x-1

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(1-(-2))/(8-(-4))

m=(1+2)/(8+4)

m=3/12

m=1/4

y-y1=m(x-x1)

y-(-2)=1/4(x-(-4))

y+2=1/4(x+4)

y=1/4x+4/4-2

y=1/4x+1-2

y=1/4x-1

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The radius of a circle with area A can be approximated using the formula r = the square root of A/3 . Estimate the radius of a w
Arturiano [62]

Answer: 12

Step-by-step explanation:

Given:

A = 452

r = √A/3

Step 1: Substitute 452sqf for A

r = √452/3

Step 2: Solve

452 ÷ 3 = 150.66∞

√150.66∞ = 12.27∞

12.27∞ rounded to the nearest integer equal 12

3 0
3 years ago
The length of a rectangle is measured as 370mm correct to 2 significant figures.
olga nikolaevna [1]

Answer:

UB: 375

Step-by-step explanation:

370mm to 2 sig figs..

UB: 375

LB:365

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5 0
3 years ago
an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a
viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is;  \mathbf{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft  is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the  rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at  a time t and r = radius of the cone shaped at a time t

Then the similar triangles  ΔOCD and ΔOAB is as follows:

\dfrac{h}{r}= \dfrac{20}{8}    ( similar triangle property)

\dfrac{h}{r}= \dfrac{5}{2}

\dfrac{h}{r}= 2.5

h = 2.5r

r = \dfrac{h}{2.5}

The volume of the water in the tank is represented by the equation:

V = \dfrac{1}{3} \pi r^2 h

V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h

V = \dfrac{1}{18.75} \pi \ h^3

The rate of change of the water depth  is :

\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

Since the water is drained  through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

\dfrac{dv}{dt}= - 4  \ ft^3/sec

Therefore,

-4 = \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

the rate of change of the water at depth h = 10 ft is:

-4 = \dfrac{ 100 \ \pi }{6.25}\  \dfrac{dh}{dt}

100 \pi \dfrac{dh}{dt}  = -4 \times 6.25

100  \pi \dfrac{dh}{dt}  = -25

\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi}

Thus, the rate of change of the water depth when the water depth is 10 ft is;  \mathtt{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

4 0
4 years ago
Subtract <br> (5x+3) -(x+2) <br><br><br><br><br>A. 4x+1<br>B. 5x+5<br>C. 4x+5<br>D. 5x+1​
miss Akunina [59]

Answer:

4x+1

Step-by-step explanation:

Collect the like therms and then substract the numbers

3 0
3 years ago
A number z is fewer than 3/4​
lozanna [386]

Answer:

z < ¾

Step-by-step explanation:

Or z < 0.75

...........

4 0
3 years ago
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