1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
chubhunter [2.5K]
3 years ago
14

Joe purchased a tray of 48 petunias to plant in his garden. The graph shows points representing the number of flowers left to pl

ant at several different times while Joe is planting.
Select from the drop-down menus to complete the equation, in standard form, that represents the relationship between the number of petunias left to plant, y, and the time, x, Joe has spent planting.
Mathematics
1 answer:
Svet_ta [14]3 years ago
7 0

Answer:

Required equation is y - 36 = (24 - 36)/(2 - 1) (x - 1)

y - 36 = -12(x - 1)

y - 36 = -12x + 12

12x + y = 12 + 36

12x + y = 48

Step-by-step explanation:

You might be interested in
Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.
Hitman42 [59]
\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\

\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}

\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
\\\\\\
\textit{and now, let's rationalize the denominator}
\\\\\\
\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}

7 0
3 years ago
HELP ASAP I give brainliest!
Bingel [31]
1. 5%

2. That’s the only answer I have, sorry.
8 0
3 years ago
An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of
ANEK [815]

Answer:

(a) 0.152

(b) 0.789

(c) 0.906

Step-by-step explanation:

Let's denote the events as follows:

<em>F</em> = The word free occurs in an email

<em>S</em> = The email is spam

<em>V</em> = The email is valid.

The information provided to us are:

  • The probability of the word free occurring in a spam message is,             P(F|S)=0.60
  • The probability of the word free occurring in a valid message is,             P(F|V)=0.04
  • The probability of spam messages is,

        P(S)=0.20

First let's compute the probability of valid messages:

P (V) = 1 - P(S)\\=1-0.20\\=0.80

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The probability that a message contains the word free is:

P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is spam provided that it contains free is:

P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is valid provided that it does not contain free is:

P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566

The probability that a message is valid provided that it does not contain free is approximately 0.906.

4 0
3 years ago
There are 10 marbles in a bag. Four are blue, 3 are black and 2 white and 1 red. If the marbles are not replaced once they are d
stich3 [128]

<u>Given</u>:

Given that there are 10 marbles in a bag. 4 are blue, 3 are black, 2 are white and 1 is red.

The marbles are selected by not replacing the drawn ones.

We need to the probability of selected a black marble and then a white marble without replacement.

<u>Probability</u>:

Let B denote the black marble.

Let W denote the white marble.

The probability of selecting a black marble is P(B)=\frac{3}{10}

The probability of selecting a white marble without replacement is P(W)=\frac{2}{9}

The probability of selecting a black marble and then a white marble without replacement is given by

P(B \ and \ W)=P(B) \cdot P(W)

Substituting the values, we get;

P(B \ and \ W)=\frac{3}{10} \cdot \frac{2}{9}

P(B \ and \ W)=\frac{6}{90}

P(B \ and \ W)=\frac{1}{15}

Thus, the probability of selecting a black marble and then a white marble without replacement is \frac{1}{15}

4 0
3 years ago
Can someome help me find the mean of this numbers? 15,16,17,18,19,20,21,22 (RANDOM ANXWERS WILL BE REPORTED)
bezimeni [28]
The mean of these numbers is 18.5
4 0
3 years ago
Read 2 more answers
Other questions:
  • I need help please is it A B C or D
    5·2 answers
  • How do you find compound interest and simple interest?
    10·1 answer
  • Let X be a random variable that is equal to the number of times a 5 is rolled in three rolls of a fair 5-sided die with the inte
    13·1 answer
  • Solve the given system of equations. 2y= -x+9 , 3x-6= -15
    14·1 answer
  • A car is traveling at a speed of yy miles per hour. Which situation would be described by the expression 1.2y1.2y? the speed of
    7·1 answer
  • Plot two points that are 3units from Point C and also share the same y-coordinate as Point C.
    11·1 answer
  • The hypotenuse of a triangle measures 20.75 in., and one of the legs measures 17 in, what is the approximate length of the other
    7·1 answer
  • Please help me, I'm so lost! If you can explain it to me, I will give brainliest!
    7·1 answer
  • Solve for x. Round to the nearest tenth, if necessary.
    14·1 answer
  • Hi I need help with this homework so I can get a good grade on the test
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!