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Darina [25.2K]
3 years ago
10

3.

Mathematics
2 answers:
zheka24 [161]3 years ago
6 0

Answer:

20

Step-by-step explanation:

Sn = (n/2)(a1 + a1 + d(n-1)), where S = sum, a1 = first term, n = number of terms, d = common difference

 

400 = (n/2)(1 + 1 + 2(n - 1))

400 = (n/2)(2  + 2n - 2)

400 = (n/2)(2n

400 = n2

20 = n

 

Twenty numbers are in the set.

Lesechka [4]3 years ago
3 0

Answer:

Step-by-step explanation:

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Triangle DNO has vertices at D(5, 8), N(– 3, 10), and O(– 3, 6). If vertex D is translated 4 units to the right, the best name f
prisoha [69]

Using distance between two points to find the lengths of the edges of the triangle, the correct option is:

b. Isosceles

The distance between two points, (x_1,y_1) and (x_2,y_2), is given by:

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Vertex D is translated 4 units to the right is (9,8).

The lengths of the edges are:

DN = \sqrt{(9 - (-3))^2 + (8 - 10)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}

DO = \sqrt{(9 - (-3))^2 + (8 - 6)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}

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<u>Two edges of the same length</u>, hence, it is an isosceles triangle, given by option b.

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6 0
2 years ago
2. To estimate the mean age for a population of 4000 employees, a simple random sample of 40 employees is selected. a. Would you
ANEK [815]

Answer:

Step-by-step explanation:

a.

Size of the population, N = 4000

Size of the sample, n = 40

n/N = 40/4000 = 0.01

0.01 is less than 0.05 and hence we would not us the finite population correction factor in calculating the standard error of the mean.

b.

Population standard deviation is σ = 8.2

<u>So, the standard error of x’ using the finite population correction factor is give by</u>

σ(x’) = √[(N - n)/(N - 1)] x (sigma/√n)

σ(x’) = √[(4000 - 40)/(4000 - 1)] x (8.2/√40)

σ(x’) = 1.29

<u>Standard error of x’ without using the finite population correction factor is</u>

σ(x’) = σ/√n

σ(x’) = 8.2/√40 = 1.2965

<u>There is little difference between the two values of the standard error. So we can ignore the population correction factor.</u>

c.

Let the population mean be μ

Probability that the sample mean will be within =-2 of the population mean is

P(μ– 2 < x’ < μ + 2)

At x’ = μ – 2 , we have

z = (μ – 2 – μ)/1.2965

z = -1.54

at x’ = μ  + 2, we have

z = (μ + 2 – μ)/1.2965

z = 1.54

<u>So the required probability is </u>

P(μ – 2 < x’ < μ + 2) = p(-1.54< z < 1.54)

P(μ – 2 < x’ < μ + 2) = p(z < 1.54) – p(z < -1.54)

P(μ – 2 < x’ < μ + 2) = 0.9382 – 0.0618

P(μ – 2 < x’ < μ + 2) = 0.8764

7 0
3 years ago
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Natali [406]

Answer: -4

Step-by-step explanation:

Solve 2x+7=-1

2x. =-8

x. =-4

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