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3 years ago

Determine the genotype of the purple flower with unknown genotype if purple (P) is dominant and white(p) is recessive

1 answer:

4 0

Here, Genotype of the Purple flower can be determined by "Test Cross", in which Cross will occur between White flower and the given flower.

Case.1) If all the offspring are purple, then the Genotype of that Flower would be: PP

Case. 2) If one of the offspring is White, then the Genotype of that Flower would be: Pp

Hope this helps!

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How many males in the 2nd generation are affected?

Step2247 [10]

I think 3 is the answer

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2 years ago

the couple is also concerned about their child inheriting hemophilia, another rare disease, which is x-linked. natalie’s brother

IgorC [24]

Hemophilia is a recessive X-linked condition and is inherited from parents. . The probability that Natalie and Daniel’s first child has hemophilia is 1/4, not 1/8. The statement is false.

<h3>What is an X-linked gene?</h3>

When talking about sex-linked genes, we refer to all those genes located in one of the sex-chromosomes and not in the somatic ones.

X-linked genes are the genes located specifically in the X sex chromosome.

Traits coded by these genes are inherited. This is, X-linked genes are transmitted from parents to children through generations.

According to this, X-linked genetic disorders will be inherited as well.

Men have a high probability of being affected since they only have one copy of the X chromosome.

In women, the effect of the mutation might be musk in heterozygous state if the mutation is recessive.

Hemophilia is a recessive X-linked disorder, which means it is coded by the recessive allele.

X+ ⇒ X chrosomosome with Dominant allele

X- ⇒ X chrosomosome with Recessive allele

Genotype Phenotype

X+X+ Healthy woman

X+X- Healthy carrier woman

X-X- Hemophilic woman

X+Y Healthy man

X-Y Hemophilic man

Let us make a pedigree of these families,

Natalie's family:

Mother healthy carrier X+X-

Father healthy X+Y

Brother hemophilic X-Y

Natalie Healthy X+X- or X+X+

Natalie has 1/2 chances of being carrier X+X- and 1/2 of being X+X+.

Daniel's family:

Mother healthy carrier X+X-

Father hemophilic X-Y

Sister hemophilic X-X-

Daniel Healthy X+Y

He has 1/2 chances of being healthy X+Y and 1/2 of being affected X-Y.

According to the product probability rule, if events A and B are independent from each other, the probability of occurrence of both events together is

P(A∩B) = P(A) x P(B)

In this case,

event A is Daniel being affected ⇒ 1/2
event B is Natalie being carrier ⇒ 1/2

P(A∩B) = P(A) x P(B) = 1/2 x 1/2 = 1/4

The probability that Natalie and Daniel’s first child has hemophilia is 1/4, not 1/8. The statement is false.

You can learn more about X-linked genes at

brainly.com/question/12420228

brainly.com/question/14704182

brainly.com/question/1387724

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lisov135 [29]

Answer:

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Explanation:

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