Answer:
Neighborhood Q appears to have a bigger family size
Step-by-step explanation:
Mean = the sum of all data values divided by the total number of data values
Number of families in Neighborhood Q = 9
Mean family size of Neighborhood Q:
= (2 + 5 + 4 + 3 + 2 + 5 + 3 + 6 + 5) ÷ 9
= 35 ÷ 9
= 3.888888...
Number of families in Neighborhood S = 9
Mean family size of Neighborhood S:
= (2 + 3 + 2 + 3 + 7 + 2 + 3 + 3 + 2) ÷ 9
= 27 ÷ 9
= 3
The mean family size of Neighborhood Q is 3.88.. and the mean family size of Neighborhood S is 3. Therefore, Neighborhood Q appears to have a bigger family size as it's average family size is bigger than that of Neighborhood S.
Answer:
20. J, 21. B
Step-by-step explanation:
20. P = 15 (2) + 8 (2)
P = 36 ft.
21. 15 - 6 = 9 ft.
First subtract the 7 from both sides and that would equal 2x+9=2x then subtract 2x and the answer is 9
Answer:
7020
Step-by-step explanation:
The letter could be any 1 of the 26 and it could be placed in any 1 of 3 places so this makes 26*3 = 78 possibilities.
For each of these there is any one of permutations of 2 digits from 10
= 10P2 = 10! / 8! = 10*9 = 90.
So the answer is 78 * 90 = 7020.
Note I am assuming that the 2 digits picked are different - no duplicates.
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