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Maksim231197 [3]
4 years ago
14

Its says use rounding or compatible numbers to estimate the sum and example 198 + 727 ans is 200+725=925 I still don't understan

d how to do it. Heres a problem 87+34 and here is one 222+203
Mathematics
2 answers:
Ede4ka [16]4 years ago
6 0
Okay, rounding is when you take a number such as 198 and imagine that it is something easier to do math with, like 200. 
200 is easier to add with because there are zeroes in the tens place and the ones place. 
725 is easier to add with than 727 because the ones place digit, (5), is an easier base to use, just like zero. 
Using the easier numbers, 200 + 725 = 925
Using the original numbers, 198 + 727 + 925
*Because you took two pieces from the 727 and added them to 198, the four numbers in this problem are compatible. 
Compatible numbers are when you use numbers that are close to the original ones and make it easier to do the problem in your head. 
____
In the case of 87+ 34, the simplest numbers to use would be 90 instead of 87 and 35 instead of 34. Not as easy as the first equation, but still doable. 
90+35+125
    or
87+34=121
____
In the case of 222+203, the simplest substitutions are 220 and 200. 
220+200=420
or
222+203=425
Hope this helps, 
Ahawk
DENIUS [597]4 years ago
3 0

Answer:

a) 121

b) 425  

Step-by-step explanation:

We are given the following information in the question:

198 + 727 + 200 + 725 = 925

This can be explained with the help of associative of addition and subtraction and commutative property of the addition.

Associative property:

a+(b+c) = (a +b )+c

Commutative property:

a+b = b+a

198 + 727 \\= 198 + ( 727 + 2)\\=198 + ( 2 + 727)\\=(198 + 2) + 725\\= 200+ 725 \\= 925

a)

87 + 34\\= 87 + ( 31 + 3)\\=87 + ( 3 + 31)\\=(87 + 3) + 31\\=90 + 31\\=121

b)

222 + 203\\=(220 + 2) + 203\\=220 + ( 2 + 203)\\=220 + 205\\=425

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The question you are asking is not that really hard. In fact it is really easy.

I will give you my examples for some question.

1. (example) The probability of the two heads shown will be more than the two tails shown\

2. Since I hit 17 / 100 (17%) for the two heads and I hit 11 / 100 (11%) for the two tails, then my (example) theory was correct since I stated that there will be more probability showing two heads than on two tails.

Basically at questions 3 & 4 (and also 5 & 6), it is the same as questions 1 & 2.

In question 1, 3, and 5, you need to state what YOU think will happen before doing the 100 coin flip.

Then in question 2, 4, and 6, you need to sate IF YOUR THEORY WAS CORRECT OR WRONG using the results you have. It does not matter if you are wrong.

I will give you my example for 1 and 2 question.

1. (example) The probability of the two heads shown will be more than the two tails shown

2. Since I hit 17 / 100 (17%) for the two heads and I hit 11 / 100 (11%) for the two tails, then my (example) theory was correct since I stated that there will be more probability showing two heads than on two tails.

Basically at questions 3 & 4 (and also 5 & 6), it is the same as questions 1 & 2.

For question number 7, the answer is because my theory is just a guess before the outcome.

You can vote how good my answer is, I just hoped I helped you clarify your misunderstandings.

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