Answer
given,
focal length of lens A = 5.77 cm
focal length of lens B= 27.9 cm
flies distance from mirror = 11.3 m
now,
Using lens formula
q =11.79 cm
image of lens A is object of lens B
distance of lens = 59.9 - 11.79 = 48.11
now, Again applying lens formula
q' =66.41 cm
hence, the image distance from the second lens is equal to q' =66.41 cm
It would be spectral class M
hope this helps
Answer:
vf=94.4 m/s
Explanation:
acceleration is the final velocity minus initial velocity divided by time
a = (vf-vi)/t
Given:
a= 14.2 m/s^2
vi= 0 (at rest)
t = 6.6
Solve for vf
a = (vf-vi)/t
a*t=vf-vi
(14.2)*(6.6)=vf - 0
vf=94.4 m/s
I posted this because I got it correct. The answer is 28J.
There is no figure, so I asume the angle of the rope is measured with respect to the horizontal direction.
If this is the case, then the magnitude of the tension is the hypothenuse of a right triangle, of which
and
(horizontal and vertical component of the tension) are the other sides, and
is the angle between T and
.
Therefore,
(the side of the triangle opposite to
) is given by the magnitude of the tension multiplied by the sine of the angle:
