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goblinko [34]
3 years ago
11

The volume of a rectangular prism is given by the formula V = lwh, where l is the length of the prism, w is the width, and h is

the height. Suppose a box in the shape of a rectangular prism has length (2a + 11), width (5a – 12), and height (a + 6). Which expression represents the volume of the box?
v=(2a+11)(5a-12)(a+6)
v=(10a^2-24a+55a-132)(a+6)
v=(10a^3+60a^2-24a^2-144a+55a^2+330a-132a-792
v=10a^3+60a^2-24a^2+55a^2-144a+330a-132a-792
v=10^3+91a^2+54a-792
Physics
1 answer:
Verizon [17]3 years ago
4 0
<span> For this case the volume of the box is given by:
</span> V = lwh&#10;
<span> Substituting values we have:
</span> V = (2a + 11) (5a - 12) (a + 6)&#10;
<span> Rewriting we have:
</span> V = (10a ^ 2-24a + 55a-132) (a + 6)&#10;&#10;V = 10a ^ 3-24a ^ 2 + 55a ^ 2-132a + 60a ^ 2-144a + 330a-792
<span> Grouping terms of equal degree we have:
</span> V = 10a ^ 3 + 60a ^ 2 -24a ^ 2 + 55a ^ 2 -132a -144a + 330a-792
<span> Adding terms of equal degree we have:
</span> V = 10 ^ 3 + 91a ^ 2 + 54a-792&#10;
<span> Answer:
 the volume of the box is:
 All the expressions given.</span>
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Answer:

v=1.93m/s

Explanation:

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3 years ago
Your friend is constructing a balancing display for an art project. She has one rock on the left ( ms=2.25 kgms=2.25 kg ) and th
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Answer:

Torque = 35.60 N.m (rounded off to 3 significant figures.

Explanation:

Given details:

The mass of the rock on the left, ms = 2.25 kg

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(a) The torque produced by the pile of rock, T = F*rp = m*g*rp

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3 years ago
calculate earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the s
IceJOKER [234]

Answer:

Hello your question is incomplete below is the complete question

Calculate Earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the sun, Take the eccentricity of Earth's orbit to be 1/60 and its Semimajor axis to be 93,000,000

answer : V = 1.624* 10^-5 m/s

Explanation:

First we have to calculate the value of a

a = 93 * 10^6 mile/m  * 1609.344 m

  = 149.668 * 10^8 m

next we will express the distance between the earth and the sun

r = \frac{a(1-E^2)}{1+Ecos\beta }   --------- (1)

a = 149.668 * 10^8

E (eccentricity ) = ( 1/60 )^2

\beta = 90°

input the given values into equation 1 above

r = 149.626 * 10^9 m

next calculate the Earths velocity of approach towards the sun using this equation

v^2 = \frac{4\pi^2 }{r_{c} }   ------ (2)

Note :

Rc = 149.626 * 10^9 m

equation 2 becomes

(V^2 = (\frac{4\pi^{2}  }{149.626*10^9})

therefore : V = 1.624* 10^-5 m/s

4 0
4 years ago
Why should a glass slide and a coverslip be held by the edges?
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THIS IS NOT THE EXACT ANSWER BUT IT MIGHT HELP
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8 0
3 years ago
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Answer:

The apparent weight of the object is 0.465 N.

Explanation:

Given that,

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Using formula of buoyancy force

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Put the value into the formula

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Using formula of apparent weight

W=F-F'

Put the value into the formula

W=0.71-0.245

W=0.465\ N

Hence, The apparent weight of the object is 0.465 N.

5 0
3 years ago
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