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Serjik [45]
3 years ago
11

The altitude of Object B is 27 times the altitude of Object A. The altitude of Object A is $3^3$ feet. What is the altitude of O

bject B? Write your answer as a power.
ft
Mathematics
1 answer:
Andrej [43]3 years ago
3 0

Answer:

3^6

Step-by-step explanation:

We know that A is 3^3 and B is 27 times that.

3•3•3=27

So B is 3•3•3• of 3^3 which is 3•3•3•3•3•3

Write the answer to the exponents which will be 3^6

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PLEASE HELP
AnnZ [28]

Answer: 7

Step-by-step explanation:

1. multiply both sides by -6 so the -6 on the right side could cancel out and the left side would be -6:  1= a-13/-6 ==> -6=a-13

2. add both sides by 13 so -13 on the right side could cancel out and the left side would be -6+13: -6=a-13 ==> -6+13=a-13+13

3. you know -6+13 equals 7 right? so the answer is a=7

5 0
3 years ago
Read 2 more answers
3. A map pencil drawer contains the following colors: 5 Purple, 3 Yellow,
natta225 [31]
Add up all the numbers together
it’ll give you 17
since they’re asking abt the probability of a purple being chosen twice, multiply 5 by 2 to give you 10
so 10/17
3 0
3 years ago
I need help on this question
BaLLatris [955]

In order for a game to be fair, both players must have the same chance of winning. Let's examinate the four games:

First game:

First player wins with 1,2,3, second player wins with 4,5,6. Both have 3 chances of winning, with a probability of 1/6 each. So, both players have a winning chance of 3/6=1/2, and thus the game is fair.

Second game:

First player wins with heads side up, second player wins with tails side up. Both have 1 chances of winning, with a probability of 1/2 each, and thus the game is fair.

Third game:

First player wins with 2,4,6, second player wins with 1,3,5. Both have 3 chances of winning, with a probability of 1/6 each. So, both players have a winning chance of 3/6=1/2, and thus the game is fair.

Fourth game:

First player wins with 3,4,5 or 6, second player wins with 1 or 2. Player 1 has four chances of winning, with a probability of 1/6 each, whereas player 2 has 2 chances of winning, with a probability of 1/6 each. So, player 1 has a winning chance of 4/6=2/3, while player 2 has a winning chance of 2/6=1/3, and thus the game is not fair.

7 0
3 years ago
What segment is congruent to PT
Nesterboy [21]
We can’t see the shape
6 0
3 years ago
Let f be the following​ piecewise-defined function. ​f(x)equals left brace Start 2 By 1 Matrix 1st Row 1st Column x squared plus
Colt1911 [192]

Answer:

the function is continuous but not differentiable  in x=3

Step-by-step explanation:

for f(x) defined as

x²+5 for x≤3

3*x+5 for x>3

then for f to be continuous then

when x→a , lim f(x) = f(a)

thus

from the left

when x→3⁻ , lim f(x) = lim x²+5 = 3²+5 = 14

from the right

when x→3⁺ , lim f(x) = lim 3*x+5 = 3*3+5 = 14

and f(3) = 3²+5 = 14

since both limits converge and are equal to f(3), then the function is continuous in 3

Nevertheless, the function is not differentiable in 3 since the curve is not smooth in f(3) ( it has an sharp change in f(3) ) , then the function is not differentiable  in x=3

to prove it , when x=3 and

when h→0⁻ , f'(x=3)= lim [f(x+h)-f(x)] /h  = lim [(x+h)²+5 - (x² + 5)]/h = lim [2*x*h+h²] /h = lim [2*x+h] = 2*3+0 = 6

when h→0⁺ , f'(x=3)= lim [f(x+h)-f(x)] /h  = lim [3*(x+h)+5 - (3*x + 5)]/h = lim [3*h] /h = lim 3 = 3

since the limits do not converge →the limit does not exist → the derivative does not exist → the function is not differentiable in x=3

4 0
3 years ago
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