The altitude of Object B is 27 times the altitude of Object A. The altitude of Object A is $3^3$ feet. What is the altitude of O
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Answer:
4.3 km
Step-by-step explanation:
The law of cosines can be used to find the desired distance. If we call the lighthouse position point L, then we have ...
CH² = LC² +LH² -2·LC·LH·cos(L)
CH² = 2² +2.5² -2·2·2.5·cos(143°) = 10.25 -10cos(143°) ≈ 18.2364
CH ≈ √18.2364 ≈ 4.27 . . . . km
The distance CH is about 4.3 km.
Answer:
h = 15 feet
Step-by-step explanation:
A right triangle is formed by the slant height, the radius of the base and h, with the slant height being the hypotenuse.
Using Pythagoras' theorem in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
Since base diameter = 16 then radius = 8
h² + 8² = 17²
h² + 64 = 289 ( subtract 64 from both sides )
h² = 225 ( take the square root of both sides )
h = = 15