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2 years ago

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The altitude of Object B is 27 times the altitude of Object A. The altitude of Object A is $3^3$ feet. What is the altitude of O

bject B? Write your answer as a power.
ft

1 answer:

Andrej [43]2 years ago

3 0

Answer:

3^6

Step-by-step explanation:

We know that A is 3^3 and B is 27 times that.

3•3•3=27

So B is 3•3•3• of 3^3 which is 3•3•3•3•3•3

Write the answer to the exponents which will be 3^6

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Masteriza [31]

Answer:

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Step-by-step explanation:

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2 years ago

Which is equal to 8^-10/8^5 ?

makkiz [27]

$8^{-10}$ can be converted into $\frac{1}{ 8^{10} }$ , and applying this to $8^{-5}$ can see that

$\frac{ \frac{1}{ 8^{10} } }{ \frac{1}{ 8^{5} } }$

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2 years ago

What’s 3 times 72 in expanded Form?

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2 years ago

Read 2 more answers

Does (2,0) work as a solution to the systems of equations to lines 3x+y=6 and 3x-y=6

fenix001 [56]

Answer:

Yes

Step-by-step explanation:

To see if (2,0) works as a solution to the systems of equations, we plug in the values of x and y and simplify. If the results are equal, then (2,0) is a solution.

3x + y = 6:

$3(2) + 0 = 6$
$6 + 0 = 6$
$6 = 6$
(2,0) is a solution to this equation.

3x - y = 6:

$3(2) - 0 = 6$
$6 - 0 = 6$
$6 = 6$
(2,0) is a solution to this equation.

Therefore, the answer is yes, it does work as a solution.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

7 0

2 years ago

MAVERICK [17]

Answer:

43°

Step-by-step explanation:

Calculating for the measure of angle C using

<h3>sine rule</h3>

$\frac{sin18}{9} = \frac{sinc}{20} \\ sinc = \frac{sin18 \times 20}{9} \\ sinc = 0.6867 \\ c = \csc(0.6867) \\ c = 43.3869 \\ c = 43 \: degrees$

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1 year ago