Answer: The frequency at which frames in a television picture, film, or video sequence are displayed.
Answer:
The combined output will be option D which is
This porridge is too hot.
This porridge is just right!
Explanation:
As the complete question is not the given the complete question is found online and is attached herewith.
Now from the given attached code
As the temperature value is 180 which is more than 90 so the first loop is true and the first print out is
This porridge is too hot.
Now the temperature is cooled down using the formula such that the temperature reduced 100 degrees in the intervals of 20 now the temperature becomes 80. As it is greater than 70, thus the second if loop is not executed.
As the temperature is 80 this the next print out will be as
This porridge is just right!
So the combined output will be option D which is
This porridge is too hot.
This porridge is just right!
Answer:
Through after school programs
Explanation:
Under represented and under resourced students can be better engaged in STEM programs through the establishment of after school state of the arts learning centres that can augment for the vacuum in the regular school system.
In such programs, the use of technological platforms with an integrated electronic learning system is necessary, because it avails the students the opportunity to brace up with the evolving impact of information technology to learning and personal developments.
Secondly, the use of immediate resources within the reach of these under privileged and under resourced students is a necessity. for example, a student in a rural community could start become more engage in engineering designs, building technology, instrumentation and architecture through the use of disposed cartons used to construct buildings, cars etc.
Answer:
1. G=D+(A+C^2)*E/(D+B)^3
cobegin:
p1: (D+B)
p2: p1^3
p3: C^2
p4: A+ p3
p5: E/p2
p6: p4 * p5
p7: D + p6
:G
coend
2. Now The value A=2, B=4, C=5, D=6, and E=8
p1: 6+4 =10
p2: p1 ^3= 10^3= 1000
p3: c^2= 5^2 =25
p4: A + p3= 2 +25 =27
p5: 8/1000
p6: 27 *8/1000
p7: D+ P6= 6+ 216/1000
= 6216/1000
=6.216
Explanation:
The above, first bracket with power is processed, and then power inside and outside bracket. And rest is according to BODMAS, and one process is solved at a time.
