Answer:
76.16 kilograms of food
Step-by-step explanation:
Number of cyclist = 32
Food per cyclist = 8.33 kilograms
Days of the trip = 7 days
Food per cyclist per day = 8.33 kg / 7
= 1.19kg food per day for each cyclist
how many kilograms of food will the group be carrying at the end of Day 5?
5 days out of 7 days = 2 days
Each cyclist will have to carry = 2 × 1.19 kg of food for the remaining two days
= 2 × 1.19
= 2.38 kilograms of food for two days
32 cyclist for 2 days = 32 × 2.38 kg of food
= 76.16 kilograms of food
The group will be carrying 76.16 kilograms of food at the end of Day 5
The decimals ordered from least to greatest are as followed:
Least: 2.009
2.09
2.19
2.9
Greatest: 2.901
I hope I have helped in some way, shape or form!
You have to get r by itself on one side. Multiply both sides by 238 to cancel it out of the denominator on the left side.
You are left with r = 8 × 238 or r = 1904.
To check, plug 1904 back into the equation.
1904 ÷ 238 = 8
8 = 8 (True)
