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Talja [164]
3 years ago
7

Are these expressions equivalent 2w + 1t and 2w+ t

Mathematics
1 answer:
DochEvi [55]3 years ago
5 0

Answer:

Yes

Step-by-step explanation:

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Help solve 11 and 13 thanks mostly 11 xx
Gala2k [10]

Answer:

i also dont know

Step-by-step explanation:

8 0
3 years ago
Calculus hw, need help asap with steps.
nikdorinn [45]

Answers are in bold

S1 = 1

S2 = 0.5

S3 = 0.6667

S4 = 0.625

S5 = 0.6333

=========================================================

Explanation:

Let f(n) = \frac{(-1)^{n+1}}{n!}

The summation given to us represents the following

\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=\sum_{n=1}^{\infty} f(n)\\\\\\\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=f(1) + f(2)+f(3)+\ldots\\\\

There are infinitely many terms to be added.

-------------------

The partial sums only care about adding a finite amount of terms.

The partial sum S_1 is the sum of the first term and nothing else. Technically it's not really a sum because it doesn't have any other thing to add to. So we simply say S_1 = f(1) = 1

I'm skipping the steps to compute f(1) since you already have done so.

-------------------

The second partial sum is when things get a bit more interesting.

We add the first two terms.

S_2 = f(1)+f(2)\\\\S_2 = 1+(-\frac{1}{2})\\\\S_2 = \frac{1}{2}\\\\S_2 = 0.5\\\\\\

The scratch work for computing f(2) is shown in the diagram below.

-------------------

We do the same type of steps for the third partial sum.

S_3 = f(1)+f(2)+f(3)\\\\S_3 = 1+(-\frac{1}{2})+\frac{1}{6}\\\\S_3 = \frac{2}{3}\\\\S_3 \approx 0.6667\\\\\\

The scratch work for computing f(3) is shown in the diagram below.

-------------------

Now add the first four terms to get the fourth partial sum.

S_4 = f(1)+f(2)+f(3)+f(4)\\\\S_4 = 1+(-\frac{1}{2})+\frac{1}{6}-\frac{1}{24}\\\\S_4 = \frac{5}{8}\\\\S_4 \approx 0.625\\\\\\

As before, the scratch work for f(4) is shown below.

I'm sure you can notice by now, but the partial sums are recursive. Each new partial sum builds upon what is already added up so far.

This means something like S_3 = S_2 + f(3) and S_4 = S_3 + f(4)

In general, S_{n+1} = S_{n} + f(n+1) so you don't have to add up all the first n terms. Simply add the last term to the previous partial sum.

-------------------

Let's use that recursive trick to find S_5

S_5 = [f(1)+f(2)+f(3)+f(4)]+f(5)\\\\S_5 = S_4 + f(5)\\\\S_5 = \frac{5}{8} + \frac{1}{120}\\\\S_5 = \frac{19}{30}\\\\S_5 \approx 0.6333

The scratch work for f(5) is shown below.

7 0
3 years ago
What is the slope of this equation = -0.3x + 3.7.​
meriva

Answer:

- 0.3

Step-by-step explanation:

Slope Intercept Form:

y = mx + b

Slope:

m = slope

Equation:

- 0.3x + 3.7

Slope = - 0.3

Hope This Helps :)

5 0
3 years ago
Which of the binomials below is a factor of this trinomial?<br> 4x2 + 21x + 5
guapka [62]

Answer:

B.  4x + 1

Step-by-step explanation:

4x^2 + 21x + 5

= (4x + 1)(x + 5)

Factors of this trinomial are (4x + 1) and (x + 5)

Answer

(4x + 1)

8 0
3 years ago
X+y=1<br> x+3y=9<br><br> Solve<br> (First answer gets brainliest)
Firdavs [7]
X + y = 1
x + 3y = 9

Subtract the second equation from the first.
-2y = -8
divide both sides by -2
y = 4

Plug 4 back into either equation and solve for x.
x + y = 1
x + 4 = 1
subtract 4 from each side
x = -3
(-3, 4)
8 0
3 years ago
Read 2 more answers
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