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3 years ago

Modeling Compound Interest In Exercise, complete the table for an account in which interest is compounded continuously.

Mathematics

1 answer:

Mademuasel [1]3 years ago

6 0

Answer:

This problem requires us to calculate, the value of investment after 10 and 25 years, and also tell the time after which intial investment amount will double. Investment rate and initial investment amount is given in the question.

Value of investment after 10 year = 600(1+8%)^10 = $ 1,295

Value of investment after 25 year = 600(1+8%)^25 = $ 4,109

Time after which investment amount double (n)

1200 = 600 (1.08)^n

Log 2 = n log 1.08

n = 9 years

You might be interested in

If three prime numbers are randomly selected from the prime numbers less than 30 and no prime number can be chosen more than onc

Dmitry [639]

Answer:

C)30%

Step-by-step explanation:

Prime numbers less than 30 are given below

2,3,5,7,11,13,17,19,23,29

We have to find the probability that sum of three prime numbers selected will be even.

We know that

Sum of any three prime number except 2 will be odd.

Total prime numbers except 2=9

Total prime numbers=10

Probability:P(E)= $\frac{favorable\;cases}{total\;number\;of\;cases}$

Probability of getting sum of three prime numbers selected will be odd= $\frac{9C_3}{10C_3}$

$nC_r=\frac{n!}{r!(n-r)!}$

By using formula

Probability of getting sum of three prime numbers selected will be odd=P(E)= $\frac{\frac{9!}{3!6!}}{\frac{10!}{3!7!}}=\frac{9!}{3!6!}\times \frac{3!\times 7\times 6!}{10\times 9!}$

Probability of getting sum of three prime numbers selected will be odd=P(E)= $0.7$

Probability of getting sum of three prime numbers selected will be even=P(E')=1-0.7=0.3= $0.3\times 100=30$ %

By using formula P(E')=1-P(E)

3 0

3 years ago

I NEED HELP ASAP ILL GIVE BRAINLIEST AND 30 points

raketka [301]

The question you are asking is not that really hard. In fact it is really easy.

I will give you my examples for some question.

1. (example) The probability of the two heads shown will be more than the two tails shown\

2. Since I hit 17 / 100 (17%) for the two heads and I hit 11 / 100 (11%) for the two tails, then my (example) theory was correct since I stated that there will be more probability showing two heads than on two tails.

Basically at questions 3 & 4 (and also 5 & 6), it is the same as questions 1 & 2.

In question 1, 3, and 5, you need to state what YOU think will happen before doing the 100 coin flip.

Then in question 2, 4, and 6, you need to sate IF YOUR THEORY WAS CORRECT OR WRONG using the results you have. It does not matter if you are wrong.

I will give you my example for 1 and 2 question.

1. (example) The probability of the two heads shown will be more than the two tails shown

Basically at questions 3 & 4 (and also 5 & 6), it is the same as questions 1 & 2.

For question number 7, the answer is because my theory is just a guess before the outcome.

You can vote how good my answer is, I just hoped I helped you clarify your misunderstandings.

5 0

4 years ago

One ribbon is 2 feet long the other is 30 inches which length is longer

Lubov Fominskaja [6]

30 inches is longer than 2 feet

6 0

4 years ago

What’s the answer to this question?

kobusy [5.1K]

The answer is 16.

First of all, you need to divide 4 by 1/4.

4/1 / 1/4 = 1.

15 - 1 + 2

Next, you go from left to right with addition and subtraction, so subtract 1 from 15 first.

15 - 1 = 14

14 + 2

Finally, add 14 and 2.

14 + 2 = 16.

7 0

3 years ago

While attending a film festival you decide that there are 13 movies that you are interested in seeing. However, you only have ti

kifflom [539]

<span>A. 8,648,640
B. 13
C. 665,280
D. 4,324,320
</span>Assume you don't watch movies twice.
If you have 13 movies to pick from, then you have 13 choices for the first movie. Then, only 12 choices are left. Do this until only 6 are left (13-7=6)
This equates to $13*12*11*10*9*8*7=8,648,640$
Therefore, the answer is A, 8,648,640 different ways.

Hope this helps!

5 0

3 years ago

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