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3 years ago

1/2x-3=2-3/4x Please solve

Mathematics

2 answers:

Tcecarenko [31]3 years ago

8 0

It's 4
It's easy
Use math app

Oduvanchick [21]3 years ago

3 0

Answer:

Step-by-step explanation:

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The price of a technology stock was $9.83 yesterday. Today, the price fell to $9.74 . Find the percentage decrease.

amid [387]

(9.83-9.74)=0.09
(0.09/9.83)(100)=0.9155645982%

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4 years ago

Can somebody please help me with this

EastWind [94]

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3 years ago

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Find mZA. Round the answer to the nearest whole degree.<br> A. 31°<br> B. 499<br> C. 650<br> D. 90°

choli [55]

Answer:

I haven't done this in a while but I'm pretty sure it's C.

Step-by-step explanation:

A triangle has to have 180 degrees. angle a and c are congruent. angle b is slightly smaller. therofore, istead of all the angles biegh 60, a and c are 65 thus leaving angle b 50 degrees

7 0

3 years ago

Write an expression that represents the area of only the red shaded region in terms of x

julsineya [31]

Answer:

(9 × 3x+7) - (5 × x+2)

Step-by-step explanation:

Red area

9 × 3x + 7

white area

5 × x+2

7 0

3 years ago

Two alloys A and B are being used to manufacture a certain steel product. An experiment needs to be designed to compare the two

sveta [45]

Answer:

Step-by-step explanation:

From the given information, we can compute the table showing the summarized statistics of the two alloys A & B:

Alloy A Alloy B

Sample mean $\bar {x} _A = 49.5$ $\bar {x} _B = 45.5$

Equal standard deviation $\sigma_A = 5$ $\sigma_B= 5$

Sample size $n_A = 30$ $n_{B}= 30$

Mean of the sampling distribution is :

$\mu_{\bar{X_1}-\bar{X_2}}= 49.5-45.5 \\ \\ = 4.0$

Standard deviation of sampling distribution:

$\sigma_{\bar{x_1}-\bar{x_2} }= \sqrt{\sigma^2_{\bar{x_1}-\bar{x_2} }} \\ \\ = \sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma^2_2}{n_2} } \\ \\ =\sqrt{\dfrac{25}{30}+\dfrac{25}{30}} \\\\=\sqrt{1.667} \\ \\ =1.2909$

Hypothesis testing.

Null hypothesis: $H_o: \mu_A -\mu_B = 0$

Alternative hypothesis: $H_A:\mu_A -\mu_B > 4$

The required probability is:

$P(\overline X_A - \overline X_B>4|\mu_A - \mu_B) = P\Big (\dfrac{(\overline X_A - \overline X_B)-\mu_{X_A-X_B}}{\sigma_{\overline x_A -\overline x_B}} > \dfrac{4 - \mu_{X_A-\overline X_B}}{\sigma _{\overline x_A - \overline X_B}} \Big) \\ \\ = P \Big( z > \dfrac{4-0}{1.2909}\Big) \\ \\ = P(z \ge 3.10)\\ \\ = 1 - P(z < 3.10) \\ \\ \text{Using EXCEL Function:} \\ \\ = 1 - [NORMDIST(3.10)] \\ \\ = 1- 0.999032 \\ \\ 0.000968 \\ \\ \simeq 0.0010$

This implies that a minimal chance of probability shows that the difference of 4 is not likely, provided that the two population means are the same.

Since the P-value is very small which is lower than any level of significance.

Then, we reject $H_o$ and conclude that there is enough evidence to fully support alloy A.

3 0

3 years ago