![\sqrt{96x^2y}=\sqrt{16\cdot6\cdot x^2\cdot y}=\sqrt{16}\cdot\sqrt6\cdot\sqrt{x^2}\cdot\sqrt{y}\\\\=4\cdot\sqrt6\cdot x\cdot\sqrt{y}=4x\sqrt{6y}](https://tex.z-dn.net/?f=%5Csqrt%7B96x%5E2y%7D%3D%5Csqrt%7B16%5Ccdot6%5Ccdot%20x%5E2%5Ccdot%20y%7D%3D%5Csqrt%7B16%7D%5Ccdot%5Csqrt6%5Ccdot%5Csqrt%7Bx%5E2%7D%5Ccdot%5Csqrt%7By%7D%5C%5C%5C%5C%3D4%5Ccdot%5Csqrt6%5Ccdot%20x%5Ccdot%5Csqrt%7By%7D%3D4x%5Csqrt%7B6y%7D)
========================================================
17/24
Take 1/6 multiply it by 4 and get 4/24
Take 7/8 multiply it by 3 and get 21/24
Subtract 4 from 21
Answer is 17/24
Answer:
The answer is $3600 I hope this is helpful.
Answer:
- Library 2 charges more for each book loaned.
- Library 1 has a cheaper subscription fee.
Step-by-step explanation:
Based on the table, we can write the equation for the cost of borrowing from Library 2 using the two-point form of the equation of a line:
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
for (x1, y1) = (2, 15.50) and (x2, y2) = (8, 26) this equation becomes ...
y = (26 -15.50)/(8 -2)(x -2) +15.50 . . . . . fill in the values
y = (10.50/6)(x -2) +15.50 . . . . . . . . . . . . simplify a bit
y = 1.75x -3.50 +15.50 . . . . . . simplify more
In the above, we have x = number of books; y = cost. We can use "n" and "C" for those, respectively, as in the equation for Library 1. Then the monthly cost for Library 2 is ...
C = 12 + 1.75n . . . . . . . arranged to the same form as for Library 1
_____
Now, we can answer the questions.
Library 2 charges more for each book loaned. (1.75 vs 1.50 for Library 1)
Library 1 has a cheaper subscription fee. (10 vs 12 for Library 2)
_____
The numbers in the cost equations are ...
C = (subscription fee) + (cost per book loaned)·n