<u>Answer:</u>
Michelle purchased 25 audio files in January. The percent increase is 60%
<u>Solution:
</u>
Given Data:
Michelle purchases = 25 audio files in January
Again purchased = 40 audio files in February
We need to find the percent increase for the given data.
Step 1:
Use the formula for percent change
,
Step 2:
First we find the amount of change from the question.
Amount of change = 40 – 25
By subtracting, we get 15.
Step 3:
substitute the values in formula we get,
Formula percent change = 
= 0.6
Percent = 0.6 
100 = 60 %.
Result:
Michelle purchased 25 audio files in January. And In February she purchased 40 audio files. Hence the percent increase is 60%.
The answer is 105c sqrt(3c)
A \greenD{4\,\text{cm} \times 6\,\text{cm}}4cm×6cmstart color greenD, 4, space, c, m, times, 6, space, c, m, end color greenD re
gayaneshka [121]
Answer:
356 cm².
Step-by-step explanation:
Step one: The first thing to do here is to Calculate the area of rectangle. The area of the rectangle can be calculated by using the formula below;
Area of rectangle = width × length = 6 × 4 = 24 cm².
Step two: the next step is to calculate the area of the circle. The area of the circle can be calculated by using the formula below;
Area of a circle = (radius)^2 × π.
Area of a circle = (11)^2 × π = 380.13 cm².
Step three: the next thing to do is to calculate the area of the shaded region which is the difference between the Area of a circle and the Area of rectangle.
That is; 380.13 cm² - 24 cm² = 356.13 cm².
Answer:
a) The attached pictures show the line number and the plot of the numbers.
b) The opposite of a number is the same distance from zero in the opposite way.
Step-by-step explanation:
The attached pictures show the number line with the three numbers and their respective opposites.
To find the opposite of a number, we need to find the number of places on the scale from zero. Then, we count the same number of places from zero in the opposite way.
if you ever wonder why multiplying both sides the LCD of all equations, is just to get rid of the fractions.
