Answer:
Explanation:
From the equation attached , is reduced. This is because reduction is equivalent to decrease in the oxidation number. In the equation , The oxidation number of Ni is reduced from +2 to 0.
NB, The oxidation number of a neutral atom is zero
Answer:
The answer to the question above is
The energy required to heat 87.1 g acetone from a solid at -154.0°C to a liquid at -42.0°C = 29.36 kJ
Explanation:
The given variables are
ΔHfus = 7.27 kJ/mol
Cliq = 2.16 J/g°C
Cgas = 1.29 J/g°C
Csol = 1.65 J/g°C
Tmelting = -95.0°C.
Initial temperature = -154.0°C
Final temperature = -42.0°C?
Mass of acetone = 87.1 g
Molar mass of acetone = 58.08 g/mol
Solution
Heat required to raise the temperature of solid acetone from -154 °C to -95 °C or 59 °C is given by
H = mCsolT = 87.1 g* 1.65 J/g°C* 59 °C = 8479.185 J
Heat required to melt the acetone at -95 °C = ΔHfus*number of moles =
But number of moles = mass÷(molar mass) = 87.1÷58.08 = 1.5
Heat required to melt the acetone at -95 °C =1.5 moles*7.27 kJ/mol = 10.905 kJ
The heat required to raise the temperature to -42 degrees is
H = m*Cliq*T = 87.1 g* 2.16 J/g°C * 53 °C = 9971.21 J
Total heat = 9971.21 J + 10.905 kJ + 8479.185 J = 29355.393 J = 29.36 kJ
The energy required to heat 87.1 g acetone from a solid at -154.0°C to a liquid at -42.0°C is 29.36 kJ
Answer:All the above
Explanation:
Non-ideal solutions are those solutions which do not obey Raoult's law in any conditions.
The molecular interactions of two components that is solute and solvent are different.
If there are two components A and B then the molecular interaction between A-A,B-B would be different from the molecular interactions in A-B .
The enthalpy of mixing and volume of mixing for non-ideal solutions have non zero values.
Enthalpy of mixing can be negative or positive in case of non-ideal solutions. If the enthalpy of mixing is negative so energy has been released upon mixing the two components and if enthalpy of mixing is positive then energy is absorbed upon mixing the two components.
Non-ideal solutions are simply those solutions which are not ideal hence they should not be having the characterstics of ideal solutions.
For ideal solutions the molecular interactions between the two components are equal.
So the molecular interaction between A-A,B-B would be equal to the molecular interaction between A-B. Also the enthalpy of mixing and volume of mixing for ideal solutions are zero hence all the statements provided here are correctly charactersing non-ideal solutions.
Answer:
Percent yield of PI3 = 95.4%
Explanation:
This is the reaction:
2P (s) + 3I2 (g) > 2PI3 (g)
Let's determine the moles of iodine that has reacted.
58.6 g / 253.8 g/mol = 0.231 mol
Ratio is 3:2. Let's make a rule of three to state the moles produced at 100 % yield reaction.
3 moles of I2 react to make 2 moles of PI3
0.231 moles of I2 would make (0.231 .2) / 3 = 0.154 moles of PI3
As we have produced 0.147 moles let's determine the percent yield.
(Yield produced / Theoretical yield) . 100 > (0.147 / 0.154) . 100 = 95.4%
