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Alex73 [517]
3 years ago
12

Why is rock material not gained or lost in the rock cycle

Chemistry
1 answer:
Mariulka [41]3 years ago
8 0
Matter cant be destroyed or created so if a rock erodes the rock material will just go somewhere else it wont be destroyed
You might be interested in
Substance being reduced?​
lana [24]

Answer:

Ni^{2+}

Explanation:

From the equation attached , Ni^{2+} is reduced. This is because reduction is equivalent to decrease in the oxidation number. In the equation , The oxidation number of Ni is reduced from +2 to 0.

NB, The oxidation number of a neutral atom is zero

4 0
4 years ago
How much energy is required to heat 87.1 g acetone (molar mass=58.08 g/mol) from a solid at -154.0°C to a liquid at -42.0°C? The
WARRIOR [948]

Answer:

The answer to the question above is

The energy required to heat 87.1 g acetone from a solid at -154.0°C to a liquid at -42.0°C = 29.36 kJ

Explanation:

The given variables are

ΔHfus = 7.27 kJ/mol

Cliq = 2.16 J/g°C

Cgas = 1.29 J/g°C

Csol = 1.65 J/g°C

Tmelting = -95.0°C.

Initial temperature = -154.0°C

Final temperature = -42.0°C?

Mass of acetone = 87.1 g

Molar mass of acetone = 58.08 g/mol

Solution

Heat required to raise the temperature of solid acetone from -154 °C to -95 °C or 59 °C is given by

H = mCsolT = 87.1 g* 1.65 J/g°C* 59 °C = 8479.185 J

Heat required to melt the acetone at -95 °C = ΔHfus*number of moles =

But number of moles = mass÷(molar mass) = 87.1÷58.08 = 1.5

Heat required to melt the acetone at -95 °C =1.5 moles*7.27 kJ/mol = 10.905 kJ

The heat required to raise the temperature to -42 degrees is

H = m*Cliq*T = 87.1 g* 2.16 J/g°C * 53 °C = 9971.21 J

Total heat = 9971.21 J + 10.905 kJ + 8479.185 J = 29355.393 J = 29.36 kJ

The energy required to heat 87.1 g acetone from a solid at -154.0°C to a liquid at -42.0°C is 29.36 kJ

4 0
4 years ago
The atom cobalt has 27 electrons. how many energy levels will its electrons use?
Natasha2012 [34]
It uses 4 energy levels
5 0
3 years ago
What are the characteristics of non-ideal solutions? a. The solute-solute and solvent- solvent interaction is different fromm th
finlep [7]

Answer:All the above

Explanation:

Non-ideal solutions are those solutions which do not obey Raoult's law in any conditions.

The molecular interactions of two components that is solute and solvent  are different.

If there are two components A and B then the molecular interaction between A-A,B-B would be different from the molecular interactions in A-B .

The enthalpy of mixing and volume of mixing for non-ideal solutions have  non zero values.

Enthalpy of mixing can be negative or positive in case of non-ideal solutions. If the enthalpy of mixing is negative so energy has been  released upon mixing the two components and if enthalpy of mixing is positive then energy is absorbed upon mixing the two components.

Non-ideal solutions are simply those solutions which are not ideal hence they should not be having the characterstics of ideal solutions.

For ideal solutions the molecular interactions between  the two components are equal.

So the molecular interaction between A-A,B-B  would be equal to the molecular interaction between A-B. Also the enthalpy of mixing and volume of mixing for ideal solutions are zero hence all the statements provided here are correctly charactersing non-ideal solutions.

4 0
4 years ago
Consider the balanced chemical reaction when phosphorus and iodine react to produce phosphorus triodide: 2 P(s) + 3 I2(g) → 2 PI
melamori03 [73]

Answer:

Percent yield of PI3 = 95.4%

Explanation:

This is the reaction:

2P (s) + 3I2 (g) > 2PI3 (g)

Let's determine the moles of iodine that has reacted.

58.6 g / 253.8 g/mol = 0.231 mol

Ratio is 3:2. Let's make a rule of three to state the moles produced at 100 % yield reaction.

3 moles of I2 react to make 2 moles of PI3

0.231 moles of I2 would make (0.231 .2) / 3 = 0.154 moles of PI3

As we have produced 0.147 moles let's determine the percent yield.

(Yield produced / Theoretical yield) . 100 > (0.147 / 0.154) . 100 = 95.4%

5 0
3 years ago
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