3 years ago

How many grams of sodium sulfate react with 20.8 of barium chloride?

1 answer:

3 0

<span>Convert mass of BaCl2 to moles:
20.8 g BaCl2 / 208.23 = 0.100 mol
Because BaCl2 and Na2SO4 react in a 1:1 ratio, you will need 0.100 mol Na2SO4
Mass Na2SO4 = 0.100 mol X 142 g/mol = 14.2 g Na2SO4</span>

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