Answer:
The answer is A: 0.8 moles
Explanation:
Answer: The molecular formula of the compound is 
Explanation:
Converting all these percentages into mass.
We take the total mass of the compound to be 100 grams, so, the percentages given for each element becomes its mass.So, the mass of each element is equal to the percentage given.
Mass of N = 30.45 g
Mass of O = 69.55 g
Step 1 : convert given masses into moles.
Moles of N=
Moles of O = 
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For N = 
For O =
The ratio of N: O = 1: 2
Hence the empirical formula is
.
Empirical mass of
is = 14(1)+16 (2)=46
The equation used to calculate the valency is:

Step 3: To calculate the molecular formula=
Hence, the molecular formula of the compound is 
С. product of mixing acids and bases.
Answer: 0.635 M
Explanation:
Molarity : It is defined as the number of moles of solute present per liter of the solution.
Formula used :

where,
n= Moles=
= volume of solution = 150 ml


as 1 mole of
gives 3 moles of
ions
Thus molarity of
= 
Molarity of
= 0.635 M
Answer:
49.3% 81Br and 50.7% 79Br or
81Br and
79BR
Step-by-step explanation:
To get the fraction-of-occurrences of the isotopes we must write the following equation. x is the isotopic abundance of 81Br, we can use 1 - x to get the isotopic abundance of 79Br.
(78.918)(1 - x) + (80.916)(x) = 79.903
78.918 - 78.918x + 80.916x = 79.903
1.998x = 0.985
x = 0.493
0.493 × 100 = 49.3% 81Br
100 - 49.3 = 50.7% 79Br
49.3% 81Br and 50.7% 79Br or
81Br and
79BR