Answer:
m∠1=80°, m∠2=35°, m∠3=33°
Step-by-step explanation:
we know that
The sum of the interior angles of a triangle must be equal to 180 degrees
step 1
Find the measure of angle 1
In the triangle that contain the interior angle 1
∠1+69°+31°=180°
∠1+100°=180°
∠1=180°-100°=80°
step 2
Find the measure of angle 2
In the small triangle that contain the interior angle 2
∠2+45°+(180°-∠1)=180°
substitute the value of angle 1
∠2+45°+(180°-80°)=180°
∠2+45°+(100°)=180°
∠2+145°=180°
∠2=180°-145°=35°
step 3
Find the measure of angle 3
In the larger triangle that contain the interior angle 3
(∠3+31°)+69°+47°=180°
∠3+147°=180°
∠3=180°-147°=33°
Answer:
ohk where is test
Step-by-step explanation:
and question
Answer:
24 years
Step-by-step explanation:
let jiri's age be x
Pamela's age=x-15
x+x-15=33
2x-15=33
collect the like terms to similar places
2x=33+15
2x=48
x=24
Answer:
B. 8 x 10^3
Step-by-step explanation:
1.6 x 10^5 / 0.2 x 10^2
= 160 000 / 20
= 8 000
You can write this as 8 x 10^3
Answer:
Instantaneous Velocity at t = 1 is 20 feet per second
Step-by-step explanation:
We are given he following information in the question:
![y(t)=43t-23t^{2}](https://tex.z-dn.net/?f=y%28t%29%3D43t-23t%5E%7B2%7D)
B) Instantaneous Velocity at t = 1
![y(1) = 43(1)-23(1)^2 = 20](https://tex.z-dn.net/?f=y%281%29%20%3D%2043%281%29-23%281%29%5E2%20%3D%2020)
A) Formula:
Average velocity =
![\displaystyle\frac{\text{Displacement}}{\text{Time}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7B%5Ctext%7BDisplacement%7D%7D%7B%5Ctext%7BTime%7D%7D)
1) 0.01
![y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}](https://tex.z-dn.net/?f=y%281%20%2B%200.01%29%3Dy%281.01%29%20%3D%2043%281.01%29-23%281.01%29%5E%7B2%7D%20%3D%2019.9677%5C%5C%5C%5C%5Ctext%7BAverage%20Velocity%7D%20%3D%20%5Cdfrac%7By%281.01%29-y%281%29%7D%7B1.01-1%7D%20%3D%5Cdfrac%7B19.9677-20%7D%7B1.01-1%7D%3D%20%5Cdfrac%7B-0.0323%7D%7B0.01%7D%20%3D%20-3.230000%20%5Ctext%7Bfeet%20per%20second%7D)
2) 0.005 s
![y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}](https://tex.z-dn.net/?f=y%281%20%2B%200.005%29%3Dy%281.005%29%20%3D%2043%281.005%29-23%281.005%29%5E%7B2%7D%20%3D%2019.984425%5C%5C%5C%5C%5Ctext%7BAverage%20Velocity%7D%20%3D%20%5Cdfrac%7By%281.005%29-y%281%29%7D%7B1.005-1%7D%20%3D%5Cdfrac%7B19.984425-20%7D%7B1.005-1%7D%20%3D%20-3.1150000%20%5Ctext%7Bfeet%20per%20second%7D)
3) 0.002 s
![y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}](https://tex.z-dn.net/?f=y%281%20%2B%200.002%29%3Dy%281.002%29%20%3D%2043%281.002%29-23%281.002%29%5E%7B2%7D%20%3D%2019.993908%5C%5C%5C%5C%5Ctext%7BAverage%20Velocity%7D%20%3D%20%5Cdfrac%7By%281.002%29-y%281%29%7D%7B1.002-1%7D%20%3D%5Cdfrac%7B19.993908-20%7D%7B1.002-1%7D%20%3D%20-3.0460000%20%5Ctext%7Bfeet%20per%20second%7D)
4) 0.001 s
![y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}](https://tex.z-dn.net/?f=y%281%20%2B%200.001%29%3Dy%281.001%29%20%3D%2043%281.001%29-23%281.001%29%5E%7B2%7D%20%3D%2019.996977%5C%5C%5C%5C%5Ctext%7BAverage%20Velocity%7D%20%3D%20%5Cdfrac%7By%281.001%29-y%281%29%7D%7B1.001-1%7D%20%3D%5Cfrac%7B19.996977-20%7D%7B1.001-1%7D%20%3D%20-3.0230000%20%5Ctext%7Bfeet%20per%20second%7D)