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elena-14-01-66 [18.8K]

3 years ago

5

A car is traveling at 45mph. What is the equation that models the total distance d traveled after h. What is the graph of the eq

uation

1 answer:

Ostrovityanka [42]3 years ago

4 0

D=45h

For example: 45mph times 2 hours equals 90 miles traveled

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Multiply. Write your answer as a fraction in simplest form.<br> −3/5 × 8/6=

user100 [1]

I think the answer is -4/5

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3 years ago

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natita [175]

3x-12 ≥7x+4
Subtract 3x from both sides
-12 ≥4x+4
Subtract 4 from both sides
-16 ≥4x
Divide each side by 4
-4 ≥x
From point 4, you use a closed circle and the arrow is facing towards 0

6 0

3 years ago

The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc

BaLLatris [955]

Answer:

$y(t)= 6-3cos(\dfrac{2\pi}{14}t )$

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

$y(t) = y_0+Acos(wt)$

The tide varies between 3ft and 9ft, which means its amplitude $A$ is

$A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}$

and its midline $y_0$ is

$y_o=3+3 \\\\\boxed{y_o= 6ft}$ .

Furthermore, since at $t=0$ the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is $-cos(\omega t)$ .

The period of the full cycle is 14 hours, which means

$\omega t =2\pi$

$\omega (t+14)= 4\pi$

giving us

$\boxed{\omega = \dfrac{2\pi}{14}.}$

With all of the values of the variables in place, the function modeling the situation now becomes

$\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}$

8 0

3 years ago

I need help for number 5. Plz

iogann1982 [59]

5/3 each friend gets 3/5 of the trail mix

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3 years ago

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3241004551 [841]

k-4/3= 3

Mutiply both sides by 3 .

(3)(k-4/3)= (3)(3)

Cross out 3 and 3 , divide by 3 and then becomes k-4= 9

Move -4 to the other side

Sign changes from -4 to +4

k-4+4= 9+4

k= 13

Answer: k= 13

6 0

2 years ago