Answer:
Simplification of the given expression gives value of x = 24.
Step-by-step explanation:
Here, the given expression is 3(x-4)+5x=9x-36
Now, by DISTRIBUTIVE PROPERTY:
A ( B - C ) = AB - AC
Simplifying the given expression step by step ,we get:
3(x-4)+5 x = 9 x - 36 ⇒ 3(x) - 3(4) + 5x = 9x - 36
or, 3x - 12 + 5x = 9x - 36
⇒ 8x - 9x = -36 + 12
or, - x = - 24
⇒ x = 24
Hence, the the simplification of the given expression, the value of x = 24.
5.15625
This can be figured out by 1 divided by 2 five times then multiplying by five:
1/2 = 0.5
0.5 / 2 = 0.25
0.25 / 2 = 0.0125
0.0625 / 2 = 0.625
0.0125 / 2 = 0.03125
multiply 0.03125 by 5 and you get 5.15625
then add 5 to get 5.15625
I haven't learned antiderivitives yet but I can try to logic it
<span>First find f′ and then find f. f′′(x)=3x^3+6x^2−x+2, f′(1)=9, f(1)=−7.
we reverse chain rule
3x^3, we know that it was a 4th degree thing, and the coefient is 3, so
4*what=3?, answer is 3/4
3/4x^4
6x^2
we know it was x^3, and the coefient is now 6 so
3*what=6? what=2
2x^3
-1x, the power was 2 and coefient is now -1, so
2 times what=-1?, -1/2
-1/2x^2
2, that is from 2x
so
</span>
<span>3/4x^4+2x^3-1/2x^2+2x=f'(x)
test x=1
(3/4)(1)+2(1)-(1/2)(1)+2(1)=
3/4+2-2/4+2=
4 and 1/4 we need to get it to 9
4 and 1/4 +what=9
answer is 4 and 3/4
so we add that to the end since it will become 0 from derivitive
</span>
<span>f'(x)=3/4x^4+2x^3-1/2x^2+2x+4 and 3/4
now reverse drivitive again
3/4x^4
exponent is 5 and coefient is 3/4
5 times what=3/4? answer is 3/20
3/20x^5
2x^3
exponent should be 4 and coefient is 2
4 times what=2? answer is 1/2
1/2x^4
-1/2x^2
exponent should be 3 and coefient is -1/2
3 times what=-1/2? answer is -1/6
-1/6x^3
2x
exponent should be 2 and coefient is 2
2 times what=2? answer is 1
1x^2
4 and 3/4 turns to (4 and 3/4)x
</span>
<span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+(4 and 3/4)x
try evaluating it for x=1
f(1)=(3/20)+(10/20)-(10/50)+1+(19/4)
f(1)=6 and 7/30
what do we add to get -7
-13 and 7/30
</span>
<span><span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+(4 and 3/4)x-13 and 7/30
</span>
</span>ANSWER
<span>f'(x)=3/4x^4+2x^3-1/2x^2+2x+19/4
</span><span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+19/4x-187/30</span>
Answer:
(a) The average cost function is 
(b) The marginal average cost function is 
(c) The average cost approaches to 95 if the production level is very high.
Step-by-step explanation:
(a) Suppose
is a total cost function. Then the average cost function, denoted by
, is

We know that the total cost for making x units of their Senior Executive model is given by the function

The average cost function is

(b) The derivative
of the average cost function, called the marginal average cost function, measures the rate of change of the average cost function with respect to the number of units produced.
The marginal average cost function is

(c) The average cost approaches to 95 if the production level is very high.
![\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})\\\\\lim _{x\to a}\left[f\left(x\right)\pm g\left(x\right)\right]=\lim _{x\to a}f\left(x\right)\pm \lim _{x\to a}g\left(x\right)\\\\=\lim _{x\to \infty \:}\left(95\right)+\lim _{x\to \infty \:}\left(\frac{230000}{x}\right)\\\\\lim _{x\to a}c=c\\\lim _{x\to \infty \:}\left(95\right)=95\\\\\mathrm{Apply\:Infinity\:Property:}\:\lim _{x\to \infty }\left(\frac{c}{x^a}\right)=0\\\lim_{x \to \infty} (\frac{230000}{x} )=0](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%28%5Cbar%7BC%7D%28x%29%29%3D%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%2895%2B%5Cfrac%7B230000%7D%7Bx%7D%29%5C%5C%5C%5C%5Clim%20_%7Bx%5Cto%20a%7D%5Cleft%5Bf%5Cleft%28x%5Cright%29%5Cpm%20g%5Cleft%28x%5Cright%29%5Cright%5D%3D%5Clim%20_%7Bx%5Cto%20a%7Df%5Cleft%28x%5Cright%29%5Cpm%20%5Clim%20_%7Bx%5Cto%20a%7Dg%5Cleft%28x%5Cright%29%5C%5C%5C%5C%3D%5Clim%20_%7Bx%5Cto%20%5Cinfty%20%5C%3A%7D%5Cleft%2895%5Cright%29%2B%5Clim%20_%7Bx%5Cto%20%5Cinfty%20%5C%3A%7D%5Cleft%28%5Cfrac%7B230000%7D%7Bx%7D%5Cright%29%5C%5C%5C%5C%5Clim%20_%7Bx%5Cto%20a%7Dc%3Dc%5C%5C%5Clim%20_%7Bx%5Cto%20%5Cinfty%20%5C%3A%7D%5Cleft%2895%5Cright%29%3D95%5C%5C%5C%5C%5Cmathrm%7BApply%5C%3AInfinity%5C%3AProperty%3A%7D%5C%3A%5Clim%20_%7Bx%5Cto%20%5Cinfty%20%7D%5Cleft%28%5Cfrac%7Bc%7D%7Bx%5Ea%7D%5Cright%29%3D0%5C%5C%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%28%5Cfrac%7B230000%7D%7Bx%7D%20%29%3D0)

First term: -9
Common difference: 7
a(n) = -9 + 7(n-1), for n = {1, 2, 3, ... }
Check: what is the first term? let n=1. Then a(1) = -9 + 7(1-1) = -9.
This is correct.