Answer:
Randomly selecting a six of diamonds - 1 / 52
Randomly selecting a 7, 8, 9 or 10 - 4 / 13
Step-by-step explanation:
There is only 1 six of diamonds in a standard deck of cards. There are 52 cards in a deck, thus the probability of pulling a six of diamonds is 1 in 52.
There are 4 of each card in a deck. so they are 4 7's, 4 8's. 4 9's and 4 10's. And there are a total of 52 cards in a deck. So the probability of pulling a 7,8,9 or 10 are 4 + 4 + 4 + 4 in 52
4 + 4 + 4 + 4 = 16
16 / 52 simplified is 4 / 13 Therefore the is a 4 in 13 chance of pulling a 7 8 9 or 10
The other ones are correct
Answer: x=y+z
Step-by-step explanation: Let x be the variable which is the price. Y is the price it cost. Z is the percent markup for the price. Hope this helps
N = no solution
-4 ( 6 - 2n ) = 30 + 8n
-24 + 8n = 30 + 8n
Subtract 8n from both sides
-24 = 30
This is invalid therefore no solution
Answer:
One Solution
Explanation:
7(y + 3) = 5y + 8
Simplify both sides of the equation
7(y + 3) = 5y + 8
(7)(y) + (7)(3) = 5y + 8 (Distribute)
7y + 21 = 5y + 8
Subtract 5y from both sides
7y + 21 − 5y = 5y + 8 − 5y
2y + 21 = 8
Subtract 21 from both sides
2y + 21 − 21 = 8 − 21
2y = −13
Divide both sides by 2
2y = −13
2y / 2 = -13 / 2
y = -13 / 2
-13 / 2 = -6.5
y = -13 / 2 or -6.5
Answer:
the third one
Step-by-step explanation:
